Which oddered pair is the the system of equation?
1 answer:
Answer:
(3, -9)
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
- Solving systems of equations by graphing
Step-by-step explanation:
<u>Step 1: Define systems</u>
-5x - 3y = 12
y = x - 12
<u>Step 2: Solve for </u><em><u>x</u></em>
<em>Substitution</em>
- Substitute in <em>y</em>: -5x - 3(x - 12) = 12
- Distribute -3: -5x - 3x + 36 = 12
- Combine like terms: -8x + 36 = 12
- Isolate <em>x</em> term: -8x = -24
- Isolate <em>x</em>: x = 3
<u>Step 3: Solve for </u><em><u>y</u></em>
- Define original equation: y = x - 12
- Substitute in <em>x</em>: y = 3 - 12
- Subtract: y = -9
<u>Step 4: Graph systems</u>
<em>Check the solution set.</em>
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l = 2w + 4
l * w = 48
We can substitute l with its value:
2w + 4 * w = 48
2w^2 + 4w - 48 = 0
2(w^2 + 2w - 24) = 0
2(w+6)(w-4) = 0
w = {4, -6}
7x-32=3
7x=3+32
7x=35
x=35/7
x=5
HOPE IT HELPS U!!
have a great day ahead ! :)
C= two step equations require all number to be whole number in order to solve.
Here is an example that disproves that:
.5x + 8= 18
<u> -8 -8</u>
<u>.5</u>x = <u>10
</u>.5 .5
x = 20 (.5 is certainly not a whole number but I solved it anyway)
Answer:
B) 4x^2y^2
Step-by-step explanation:
8x^3y^2+20x^2y^4
4(2x^3y^2+5x^2y^4)
4x^2(2xy^2+5y^4)
4x^2y^2(2x+5y^2)
So the answer is B
Answer: 460,000
your welcome btw