Yes both of the two fraction are proportion
Answer:
d
Step-by-step explanation:
the first oval's domain and the second's range. so you just choose the choice that includes all the values in the ranger.
To determine the number of those who joined the basketball camp this year, we just have to multiply the number of those who joined last year by the decimal equivalent of the percentage given. That is,
x = 88(1.25)
x = 110
Therefore, there are a total of 110 players for this years basketball camp.
Answer:
Maximum error for viscosity is 17.14%
Step-by-step explanation:
We know that everything is changing with respect to the time, "r" is changing with respect to the time, and also "p" just "v" will not change with the time according to the information given, so we can find the implicit derivative with respect to the time, and since

The implicit derivative with respect to the time would be

If we multiply everything by dt we get

Remember that the error is given by
therefore doing some algebra we get that

Since, r = 0.006 , dr = 0.00025 , p = 4*105 , dp = 2000 we get that

Which means that the maximum error for viscosity is 17.14%.
Answer:
Dados dos ángulos vecinos, ambos son complementarios si la suma de sus medidas es igual a 90° y suplementarios si esa suma de medidas es igual a 180°. Puesto que uno de los ángulos es el ángulo agudo mencionado en el enunciado, es decir, un ángulo cuya medida es mayor que 0° y menor que 90°. Entonces, el ángulo complementario debe ser inevitablemente menor que el ángulo suplementario.
Step-by-step explanation:
Dados dos ángulos vecinos, ambos son complementarios si la suma de sus medidas es igual a 90° y suplementarios si esa suma de medidas es igual a 180°. Puesto que uno de los ángulos es el ángulo agudo mencionado en el enunciado, es decir, un ángulo cuya medida es mayor que 0° y menor que 90°. Entonces, el ángulo complementario debe ser inevitablemente menor que el ángulo suplementario.