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vivado [14]
2 years ago
9

​When CP = Rs 1250 and SP = Rs 1500, find profit or loss percent ?

Mathematics
1 answer:
Alex Ar [27]2 years ago
6 0

Answer:

profit=20%

Step-by-step explanation:

profit%=sp-cp/cp×100%

=1500-1250/1250×100

=250/1250×100

=20%

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Tamika ran 120 meters in 21.6 seconds. Enrique ran 120 meters in 22.4
Alexus [3.1K]

Tamika ran the fastest time at 21.6 seconds in 120 meters because the faster you run the less time you have on your timer.

8 0
2 years ago
a square garden with a side of 150m has a square swimming pool in the very center with a side length of 25m calculate the area o
marta [7]

Answer: 21,875 sqm

Step-by-step explanation:

Step 1:

   Find the gross area of the garden.

   Square 150m = 22,500 sqm.

Step 2:

   Find the area of the pool.

   Square 25m = 625 sqm.

Step 3:

   Subtract the area of the pool from the gross area of the garden

   to find the net area of the garden.

   22,500 - 625 = 21,875 sqm.

Warning:

   Do not subtract the side length of the swimming pool from the side length

   of the garden before squaring.

7 0
3 years ago
228 + 6 =<br> R<br> What is the quotient
cricket20 [7]

228 + 6 = 224 + 6 + 4 = 230 + 4

= 234

Answer: 234

ok done. Thank to me :>

4 0
2 years ago
Someone please help me
Lilit [14]
<h3>Answer:</h3>
  1. C. (9x -1)(x +4) = 9x² +35x -4
  2. B. 480
  3. A. P(t) = 4(1.019)^t

Step-by-step explanation:

1. See the attachment for the filled-in diagram. Adding the contents of the figure gives the sum at the bottom, matching selection C.

2. If we let "d" represent the length of the second volyage, then the total length of the two voyages is ...

... (d+43) + d = 1003

... 2d = 960 . . . . . . . subtract 43

... d = 480 . . . . . . . . divide by 2

The second voyage lasted 480 days.

3. 1.9% - 1.9/100 = 0.019. Adding this fraction to the original means the original is multiplied by 1 +0.019 = 1.019. Doing this multiplication each year for t years means the multiplier is (1.019)^t.

Since the starting value (in 1975) is 4 (billion), the population t years after that is ...

... P(t) = 4(1.019)^t

7 0
2 years ago
Which relation is a function of x?<br> 1 {(1,2), (7, 6), (3, 2), (1, 0), (5, 6)}. <br> 3. x=3y²–7
avanturin [10]

9514 1404 393

Answer:

  The given graph shows a function of x.

Step-by-step explanation:

Neither 1 nor 3 is a single-valued relation for some values of x. The graph shown passes the vertical line test, so does represent a function.

The graph is a relation that is a function of x.

___

The attached graph is of the equation of 3. A vertical line will intersect the graph in more than one place, so the relation is NOT a function.

4 0
2 years ago
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