Median = 11. Sorry if wrong
If right, pls mark brainliest i wanna get virtuoso.
Have a great day
Extra 10, 10 is half of what she ordered so she received an extra 50%
Answer:
9, 12
Step-by-step explanation:
Just multiply the 3,4,5 triple by 3 and u get 9, 12, 15
Answer is QM = 18
You can find the length of QM by using Pythagorean theorem. See the attachment.
It is a quadrilateral with 4 equal congruent sides.
If SP = 30, so do the other 3 sides indicated by the tick marks on all 4 sides.
We will call side RQ = the hypotenuse
or side “c” = 30
We know RM is leg “b” = 24
Side “a” is our unknown QM
Our formula is
a^2 + b^2 = c^2
a^2 + 24^2 = 30^2
a^2 + 576 = 900
a^2 = 900 - 576
a^2 = 324
Take square root of both sides to solve a
a = 18
QM = 18
Answer:
<em>Option A; the tournament did begin with 128 teams</em>
Step-by-step explanation:
We can see that this equation is represented by compound interest, in other words an exponential function, either being exponential growth or exponential decay;
f ( x ) = a + ( b )^x, where a ⇒ start value, b ⇒ constant, x ⇒ ( almost always considered ) time, but in this case rounds
Option A; The equation is given to be t ( x ) = 128 * ( 1/2 )^x. Given by the above, 128 should represent the start value, hinting that the tournament <em>did indeed begin with 128 teams</em>
Option B; As the rounds increase the number of teams approach 128. Now mind you 128 is the start value, not the end value, which would mean that <em>this statement is false</em>
Option C; The tournament began with 1/2 teams. Theoretically that would not be possible, but besides that the tournament began with 128 teams, only differed by 1/2 times as much every round. <em>This statement is thus false</em>
Option D; This situation actually represents exponential decay. If each round the number of teams differed by 1/2 times as much, the number of teams remaining is less than before, and thus this models exponential decay, not growth<em> ( statement is false )</em>
<em>Answer : Option A; the tournament did begin with 128 teams</em>