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3 years ago

Find the value of the function f(x) = 7x^4 - 3x^3 + 2x^2 - 8x + 10 when x = 2

Mathematics

1 answer:

lidiya [134]3 years ago

3 0

Answer:

x= -25

Step-by-step explanation:

f'(x)=10x+4

Hey use Socratic for questions like this

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What arithmetic variables look like

juin [17]

Answer:

LETTERS

Step-by-step explanation:

In Arithmetic, variables look like LETTERS.

5 0

3 years ago

For the years between 1980 and 2012, the function c(x)=0.006x^3−0.48x^2+12.8x+85 approximates the number of countries that atten

Evgesh-ka [11]

Answer:

199

Step-by-step explanation:

2004 is 24 years after 1980. The polynomial remainder theorem tells you the remainder from division by x-24 will be the function value c(24). We can find the remainder/function value by evaluating the function rewritten to Horner form:

c(x) = ((0.006x -0.48)x +12.8)x +85

c(24) = ((0.006(24) -0.48)(24) +12.8)(24) +85 = (-.336(24) +12.8)(24) +85

= 4.736(24) +85 = 198.664

c(24) ≈ 199

The approximate number of countries attending the 2004 Olympics was 199.

5 0

3 years ago

Hi please help me thanksss<br>pls provide workings too thanks :)

anygoal [31]

Step-by-step explanation:

Search for questions & chapters

Class 11

>>Maths

>>Trigonometric Functions

>>Trigonometric Equations

>>Solve for x: sin x + sin 2x...

Question

Bookmark

Solve for x:sinx+sin2x+sin3x=cosx+cos2x+cos3x in the interval 0≤x≤2π.

Medium

Solution

verified

Verified by Toppr

We write the given equation as

(sinx+sin3x)+sin2x=(cosx+cos3x)+cos2x

or 2sin2xcosx+sin2x=2cos2xcosx+cos2x

or sin2x(2cosx+1)=cos2x(2cosx+1)

or (sin2x−cos2x)(2cosx+1)=0

∴sin2x−cos2x=0 or 2cosx+1=0

If sin2x−cos2x=0, then tan2x=1,

Hence 2x=nπ+π/4

or x=(4n+1)

.(1)

If 2cosx+1=0, then cosx=−1/2 (2)

∴x=2nπ±

2π

or x=

6n±2

We seek values of x in the interval 0≤x≤2π

In this interval (1) gives

x=π/8,5π/8,9π/8,13π/8. (n=0,1,2,3)

and (2) gives x=2π/3,4π/3. (for n=0,1)

Thus we get the answer

x=π/8,5π/8,2π/3,9π/8,4π/3,13π/8.

4 0

3 years ago

Which ordered pair is in Quadrant III?

Scilla [17]

(-2,-3)
I. (+,+)
II. (-,+)
III. (-,-)
IIII. (+,-)

4 0

3 years ago

The perimeter of a rectangular field is 60 meters. Its area is 200 square meters. Find its dimensions.

Vanyuwa [196]

Answer:

20 m by 10 m

Step-by-step explanation:

let w be width and l be length , then

2(l + w) = 60 ( divide both sides by 2 )

l + w = 30 ( subtract w from both sides )

l = 30 - w → (1)

lw = 200 → (2)

Substitute l = 30 - w into (2)

w(30 - w) = 200 ← distribute parenthesis on left side

30w - w² = 200 ( subtract 200 from both sides )

30w - w² - 200 = 0 ( multiply through by - 1 )

w² - 30w + 200 = 0 ← in standard form

(w - 10)(w - 20) = 0 ← in factored form

Equate each factor to zero and solve for w

w - 10 = 0 ⇒ w = 10

w - 20 = 0 ⇒ w = 20

Substitute these values into (1)

l = 30 - 10 = 20

l = 30 - 20 = 10

dimensions of field is 20 m by 10 m

4 0

2 years ago

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