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drek231 [11]
3 years ago
10

How many ways can you distribute $4$ identical balls among $4$ identical boxes?

Mathematics
1 answer:
Harman [31]3 years ago
4 0

Answer:

5 ways

Step-by-step explanation:

We have to name the cases.

1. 4 - 0 - 0 - 0

2. 3 - 1 - 0 - 0

3. 2 - 2 - 0 - 0

4. 2 - 1 - 1 - 0

5. 1 - 1 - 1 - 1

We don't name 0 - 0 - 1 - 3 or 0 - 1 - 1 - 2 etc. because it is the same thing.

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Answer:

24

Step-by-step explanation:

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Find the interest on a Principal Balance of $10,000 over the course of eight years with an interest rate of 5.5%. Do this for: S
o-na [289]
10,000$(1+0.055*8)
This is the formula of simple interest

10,000+10,000(0.055*t)
10,000$(1+0.055*8)=14,400
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What is the distance between points P(7, -2) and Q(-5, -1)?
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<span>d= 
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3 years ago
Please consider the following values for the variables X and Y. Treat each row as a pair of scores for the variables X and Y (wi
Studentka2010 [4]

Answer:

The Pearson's coefficient of correlation between the is 0.700.

Step-by-step explanation:

The correlation coefficient is a statistical degree that computes the strength of the linear relationship amid the relative movements of the two variables (i.e. dependent and independent).It ranges from -1 to +1.

The formula to compute correlation between two variables <em>X</em> and <em>Y</em> is:

r(X, Y)=\frac{Cov(X, Y)}{\sqrt{V(X)\cdot V(Y)}}

The formula to compute covariance is:

Cov(X, Y)=n\cdot \sum XY-\sum X \cdot\sum Y

The formula to compute the variances are:

V(X)=n\cdot\sum X^{2}-(\sum X)^{2}\\V(Y)=n\cdot\sum Y^{2}-(\sum Y)^{2}

Consider the table attached below.

Compute the covariance as follows:

Cov(X, Y)=n\cdot \sum XY-\sum X \cdot\sum Y

                 =(5\times 165)-(30\times 25)\\=75

Thus, the covariance is 75.

Compute the variance of X and Y as follows:

V(X)=n\cdot\sum X^{2}-(\sum X)^{2}\\=(5\times 226)-(30)^{2}\\=230\\\\V(Y)=n\cdot\sum Y^{2}-(\sum Y)^{2}\\=(5\times 135)-(25)^{2}\\=50

Compute the correlation coefficient as follows:

r(X, Y)=\frac{Cov(X, Y)}{\sqrt{V(X)\cdot V(Y)}}

            =\frac{75}{\sqrt{230\times 50}}

            =0.69937\\\approx0.70

Thus, the Pearson's coefficient of correlation between the is 0.700.

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Solve for t <br> 1/2t + 6 = -7
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