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kotegsom [21]
3 years ago
7

My chemistry book is 8 years older than my Algebra book. In 6 years the chemistry book will be twice as old as the Algebra book.

Show me the variable expressions for the 'now' ages of these books.
Mathematics
1 answer:
4vir4ik [10]3 years ago
6 0

Answer:

x + 14 = 2(x + 6)

x = 2

Step-by-step explanation:

Let

Algebra book age = x

Chemistry book age = x + 8

In 6 years time

Chemistry book age = x + 8 + 6

= x + 14

Algebra book age = x + 6

the chemistry book will be twice as old as the Algebra book.

x + 14 = 2(x+6)

x + 14 = 2x + 12

x - 2x = 12 - 14

- x = - 2

Divide both sides by -1

x = 2

Check:

Chemistry book age = x + 14

= 2 + 14

= 16

Algebra book age = x + 6

= 2 + 6

= 8

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Stepchild-by-step explanation:

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4 0
3 years ago
Read 2 more answers
The waiting times at a certain bank are normally distributed with a mean waiting time of 3.7 minutes and a standard deviation of
muminat

Answer:

From the given options we can say the correct answer is d.) 6.3

Step-by-step explanation:

The waiting times at the bank are given to be normally distributed.

The mean of the waiting time is given as  = 3.7 minutes

The given standard deviation is = 1.4 minutes

It is required to find the waiting time at the 97th percentile.

So we are required to find the time which can be said to be the waiting time which occurs with 97 % probability.

Let the time required be designated as y.

Therefore we can write p(X < y) = 0.97 (where 0.97 means the 97th percentile)

This is a left tailed test.

Using the formula from MSEXCEL to find y we get

y = NORMINV(0.97, 3.7, 1.4) = 6.333.

The other approach would to find the Z value corresponding to the probability value from the Z Table

The Z value for a probability of 0.97 gives us Z  = 1.881  .

Therefore \frac{y - 3.7}{1.4}  = 1.881. Therefore y = (1.881 × 1.4) + 3.7  = 6.33

Therefore from the given options we can say the correct answer is d.) 6.3

7 0
3 years ago
Dale drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took 7 hours. When Dale drove h
matrenka [14]
If you let X = the distance in miles from Dales's house, and understand rate = distance/ time, the rate going to mountains = x/7, and back from mountains is x/5. If dale was 18mph fast going home, the equation would be...
(coming home rate) = (going to mountain rate) + 18 which is
x/5 = x/7 + 18. Then solve for X.
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7x = 5x+630
simplify...
2x = 630, then
x = 315 .
Dale live 315 miles away from the mountains.


4 0
4 years ago
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