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3 years ago

write an expression that can be used to find 4 times 275 using mental math and properties of numbers.

2 answers:

6 0

Rough estimate: 4 times 300 = 1200

Properties of numbers: 4 times (300-25) = 4 times 300 - 4 times 25
= 1200 - 100
= 1100 (exact answer)

sashaice [31]3 years ago

4 0

(200×4) + (70×4) + (5×4)

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Find the measure of angle C of a triangle ABC, if: d m∠A = 60°+α, m∠B = 60°−α

snow_lady [41]

Answer:

m∠C = 60°

Step-by-step explanation:

we know that sum of angles of a traingle is 18 degrees.

given

m∠A = 60°+α,

m∠B = 60°−α

we have to find m∠C

m∠A + m∠B + m∠C = 180

60°+α + 60° - α +m∠C = 180

+α and -α gets cancelled

120°+m∠C = 180

=> m∠C = 180° - 120° = 60°

Thus, measure of angle c is 60°.

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3 years ago

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oee [108]

Answer:

£65

Step-by-step explanation:

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3 years ago

Find the perimeter of the triangle with vertices A(negative 2,2,3), B(4,negative 4,3), and C(7,6,4).

gayaneshka [121]

Answer:

$P\approx 28.872\,\text{units}$

Step-by-step explanation:

We are given coordinates of each of the vertices of the triangle ABC, hence we can use the distance formula to find the lengths of each of the side.

the distance formula is generally written as:

$r = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2+(z_1-z_2)^2}$

for the side AB: A(-2,2,3) and B(4,-4,3)

$AB = \sqrt{(-2-4)^2+(2-(-4))^2+(3-3)^2}$

$AB = \sqrt{(-6)^2+(6)^2+(3-3)^2}$

$AB = \sqrt{72}$

for the side BC: B(4,-4,3) and C(7,6,4)

$BC = \sqrt{(4-7)^2+((-4)-6)^2+(3-4)^2}$

$BC = \sqrt{110}$

for the side CA: C(7,6,4) and A(-2,2,3)

$CA = \sqrt{(7-(-2))^2+(6-2)^2+(4-3)^2}$

$CA = \sqrt{98}$

Now we all the sidelengths:

to find the perimeter we need to just sum the three side lengths:

$P = AB + BC + CA$

$P = \sqrt{72} + \sqrt{110} + \sqrt{98}$

$P\approx 28.872\,\text{units}$

this is the perimeter of triangle ABC

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3 years ago

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Oksanka [162]

Answer:

Step-by-step explanation:

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Find the area in the right tail more extreme than z= 3.01 in a standard normal distribution

Feliz [49]

<span>The area in the right tail more extreme than z= 3.01 in a standard normal distribution is given by

P(z > 3.01) = 1 - P(z < 3.01) = 1 - 0.99869 = 0.00131
</span>

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3 years ago