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k0ka [10]
3 years ago
5

If the measure of DEF is 76, what is the measure of DE? 20pts

Mathematics
2 answers:
Slav-nsk [51]3 years ago
8 0

Answer:  the answer is 152

Step-by-step explanation:

Evgen [1.6K]3 years ago
3 0
If the problem looks like mine, the answer is 152. 

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At what position on the number line is the red dot located?
raketka [301]

Answer:

C. 0.5..................

3 0
2 years ago
What are the factors of 3x^2 + 23x − 8?
Margaret [11]
<span>3x</span>²<span> + 23x − 8 = 3x</span>² + 24x - x - 8 = 3x(x+8) - (x+8) = (x+8)(3x-1)
8 0
3 years ago
The value of a car is $20,000. It loses 10.7% of its value every year . Find the approximate monthly decrease in value . Round y
jenyasd209 [6]

Answer:

$178.3

Step-by-step explanation:

The value of a car is $20,000

The car loses 10.7% of its value yearly

Since there are 12 months in a year then 10.7% can be represented as

10.7%/12

= 0.8916%

Therefore the approximate monthly decrease in value can be calculated as follows

= $20,000×0.8916/100

= $20,000×0.008916

= $178.3

Hence the approximate monthly decrease in value is $178.3

7 0
3 years ago
½ is the same as 0.5 and the ratio of _____.
Crazy boy [7]
1:2

Similar to the 1/2 fraction, 1:2 is a simplified ratio of a half.
6 0
2 years ago
In 4 ​minutes, a conveyor belt moves 800 pounds of recyclable aluminum from the delivery truck to a storage area. A smaller belt
kkurt [141]

Answer:

It takes 2 minutes 4 seconds to move the cans to storage area if both the belts are used.

Step-by-step explanation:

Given - In 4 ​minutes, a conveyor belt moves 800 pounds of recyclable

            aluminum from the delivery truck to a storage area. A smaller belt

            moves the same quantity of cans the same distance in 6 minutes.

To find - If both belts are​ used, find how long it takes to move the cans

              to the storage area.

Proof -

Given that,

Larger belt take 4 minutes to transfer the aluminium from delivery truck to storage area.

⇒ Time taken by Larger belt = 4 min/ shifting

Also,

Smaller belt take 6 minutes to transfer the aluminium from delivery truck to storage area.

⇒ Time taken by Smaller belt = 6 min/ shifting

Now,

As we know that Time is inversely proportional to time, so

Rate of Larger Belt = \frac{1}{4} shifting/min

Rate of Smaller Belt = \frac{1}{6} shifting/min

Now,

Let us assume that , if both belts used then,

Total time taken = x min/shifting

Then, Rate = \frac{1}{x} shifting/min

Now,

\frac{1}{4}  + \frac{1}{6}  = \frac{1}{x}

⇒\frac{6 + 4}{24} = \frac{1}{x}

⇒\frac{10}{24} = \frac{1}{x}

⇒10x = 24

⇒x = \frac{24}{10} = 2.4 minutes

∴ we get

It takes 2 minutes 4 seconds to move the cans to storage area if both the belts are used.

3 0
2 years ago
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