Since there is an addition symbol in the middle all you need to do is combine like terms/add. Your final answer should be:
p= 5s+5
Let's try to divide the sentence into multiple parts and then combine it one by one to make it easier to understand.
1. True
2 times y and 6 -------->(2y+6)
the square of the sum of "2 times y and 6" -------->(2y+6)^2
8 times "the square of the sum of 2 times y and 6"------> 8(2y+6)^2
2. True
the difference of x and 7 -------->(x-7)
9 and x -------->(9 + x)
2 times the product of the sum of
"9 and x" and "the difference of x and 7"-------> 2(9 + x) (x-7)
3. True
difference of 5 times x and 3 -------->(5x-3)
the square of the difference of 5 times x and 3------->(5x-3)^2
4. False
The description should be: the product of 7 and the square of x
the product of 7 and x -------->(7x)
the square of the product of 7 and x -------->(7x)^2
5. True
This one should be clear as it was one sentences
the sum of y squared(y^2) and three times y(3y) minus 4-------->y^2+ 3y -4
6. False
The description should be: the product of 5 and 8 times the square of x plus the sum of 20x and 8
the sum of 20x and 8 -------->20x+8
8 plus the square of x plus the sum of 20x and 8-------->8+ x^2 +20x+8
the product of 5 and.... ------->(5)(........
the product of 5 and
8 plus the square of x plus the sum of 20x and 8---->(5)(8+ x^2 +20x+8)
angleD=(7b+1)angle E=(2b+1)and angle F=(b+8)
The sample space has 36 possible pairs from 1,1 1,2 1,3 up to 6,5 and 6,6
(a). Three pairs add to 4 1,3 2,2 and 3,1 so P(4) = 3/36 = 1/12
(b). 6 pairs add to 7 so P(7) = 6/36 = 1/6
(c) 15 pairs add to less than 7 so P(<7) = 15/36 = 5/12
