Given triangle ABC with coordinates A(−6, 4), B(−6, 1), and C(−8, 0), and its image A′B′C′ with A′(−2, 0), B′(−5, 0), and C′(−6,
Zinaida [17]
Answer:
The line of reflection is at y = x+6.
Step-by-step explanation:
The perpendicular bisector of AA' is a line with slope 1 through the midpoint of AA', which is (-4, 2). In point-slope form, the equation is ...
y = 1(x +4) +2
y = x + 6 . . . . . . . line of reflection
The angle is 90° degrees.
If the -1 is not included, then your answer is 3.17.
2(3x-4)=11
3x2=6 and -4x2= -8
6x-8=11
+8 +8
6x=19
/6 /6
X= 3.17
Answer:
d
Step-by-step explanation:
