Samuel earned 18.90 working last weekend. He worked for 2 and 1 fourth hours. Which equation and solution represents e, the amou
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Let r = (t,t^2,t^3)
Then r' = (1, 2t, 3t^2)
General Line integral is:
The limits are 0 to 1
f(r) = 2x + 9z = 2t +9t^3
|r'| is magnitude of derivative vector
Fortunately, this simplifies nicely with a 'u' substitution.
Let u = 1+4t^2 +9t^4
du = 8t + 36t^3 dt
After integrating using power rule, replace 'u' with function for 't' and evaluate limits:
Then r' = (1, 2t, 3t^2)
General Line integral is:
The limits are 0 to 1
f(r) = 2x + 9z = 2t +9t^3
|r'| is magnitude of derivative vector
Fortunately, this simplifies nicely with a 'u' substitution.
Let u = 1+4t^2 +9t^4
du = 8t + 36t^3 dt
After integrating using power rule, replace 'u' with function for 't' and evaluate limits:
Answer:
<h3>⇒ A. 2 should be distributed as 2y + 12, y = 6</h3>Step-by-step explanation:
Here are the steps to solve this equation:
<u>Given:</u>
First step: 2(y+6)-4y
Use the distributive property.
<u>Distributive property:</u>
<h3>⇒ A(B+C)=AB+AC</h3>2(y+6)
2*y=2y
2*6=12
2y+12
Isolate the term of y from one side of the equations.
2y+12=4y
Subtract by 12 from both sides.
2y+12-12=4y-12
Solve.
2y=4y-12
Then, you subtract by 4y from both sides.
2y-4y=4y-12-4y
Solve.
2y-4y=-2y
-2y=-12
Divide by -2 from both sides.
Solve.
Divide the numbers from left to right.
<u>Solutions:</u>
-12/-2=6
- <u>Therefore, the correct answer is A. "2 should be distributed as 2y+12, y=6".</u>
I hope this helps. Let me know if you have any questions.