Given:
The values are
.
To find:
The values of
and
.
Solution:
We have,

...(i)
Multiply both sides by 10.
...(ii)
Subtracting (i) from (ii), we get




And,



Now, the product of a and b is:


The quotient of a and b is:



Therefore, the required values are
and
.
Answer:
∠1 = 50°
∠2 = ∠3 = 130°
Step-by-step explanation:
In an isosceles trapezoid, such as this one, the angles at either end of a base are congruent:
∠1 ≅ 50°
∠2 ≅ ∠3
The theorems applicable to transversals and parallel lines also apply to the sides joining the parallel bases. In particular, "consecutive interior angles are supplementary." That is, angles 1 and 2 are supplementary, for example.
∠2 = 180° -∠1 = 180° -50° = 130°
We already know angle 3 is congruent to this.
∠1 = 50°
∠2 = ∠3 = 130°
_____
<em>Additional comment</em>
It can be easier to see the congruence of the base angles if you remove the length of the shorter base from both bases. This collapses the figure to an isosceles triangle and makes it obvious that the base angles are congruent.
Alternatively, you can drop an altitude to the longer base from each end of the shorter base. That will create two congruent right triangles at either end of the figure. Those will have congruent corresponding angles.
Answer:
m = 35
Step-by-step explanation:
2m + m -15 = 90
3m -15 = 90
+15 +15
3m = 105
/3 /3
m = 35
To check the work just insert 35 for m:
2(35) + 35 -15 = 90
70 + 35 -15 = 90
105 - 15 = 90
90 = 90
3+1=4
As all parents would teach their babies simple math...take three candies and take one more. How many candies do you have now? Four
Answer:
- r = 12.5p(32 -p)
- $16 per ticket
- $3200 maximum revenue
Step-by-step explanation:
The number of tickets sold (q) at some price p is apparently ...
q = 150 + 25(20 -p)/2 = 150 +250 -12.5p
q = 12.5(32 -p)
The revenue is the product of the price and the number of tickets sold:
r = pq
r = 12.5p(32 -p) . . . . revenue equation
__
The maximum of revenue will be on the line of symmetry of this quadratic function, which is halfway between the zeros at p=0 and p=32. Revenue will be maximized when ...
p = (0 +32)/2 = 16
The theater should charge $16 per ticket.
__
Maximum revenue will be found by using the above revenue function with p=16.
r = 12.5(16)(32 -16) = $3200 . . . . maximum revenue
_____
<em>Additional comment</em>
The number of tickets sold at $16 will be ...
q = 12.5(32 -16) = 200
It might also be noted that if there are variable costs involved, maximum revenue may not correspond to maximum profit.