By the chain rule,
When
, we get
, so at this point the partial derivative of
with respect to
takes on a value of
Answer:
The answer is false
Step-by-step explanation:
In a sample above 30 obs like this the confidence interval is defined as
X+- t* (s/sqrt(n)) where X is the mean t the tvalue for a given confidence level, n the size of sample and s standar deviation.
To find de appropiate value of t we must see the T table where rows are degrees of freedom and columns significance level
The significance is obtained:
significance = 1 - confidence level = 1 - 0.9 = 0.10
Degrees of freedom (df) for the inteval are
df = n - 1 = 18 - 1 = 17
So we must look for the value of a t with 17 values and significance of 0.10 which in t table is 1.740 not 1.746 ( thats the t for 16 df)
Answer:
595
Step-by-step explanation:
SOLUTION STEPS
(2.0×10−3)(3.5×10)
Multiply 2 and 10 to get 20.
(20−3)×3.5×10
Subtract 3 from 20 to get 17.
17×3.5×10
Multiply 17 and 3.5 to get 59.5.
59.5×10
Multiply 59.5 and 10 to get 595.
595
1/64, because if its a negative exponent you use the reciprocal and then 4 to the fourth power is 64
