3 years ago

I need help pleaseeeeeeeee

1 answer:

6 0

Answer:

The answer is C

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Vinil7 [7]

Answer:

80% Confidence interval: (0.4603,0.7397)

Step-by-step explanation:

We are given the following in the question:

Sample mean, $\bar{x}$ = MD = 0.60 points

Sample size, n = 9

Sample variance = 0.09

Sample standard Deviation =

$=\sqrt{\text{Sample Variance}} = \sqrt{0.09} = 0.3$

80% Confidence interval:

$\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}$

Putting the values, we get,

$t_{critical}\text{ at degree of freedom 8 and}~\alpha_{0.20} = \pm 1.397$

$0.60 \pm 1.397(\frac{0.3}{\sqrt{9}} ) = 0.60 \pm 0.1397 = (0.4603,0.7397)$

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4 years ago