Answer: 9c²
<u>Step-by-step explanation:</u>
To find the Greatest Common Factor of 207c³ and 108c², first factor them down to their primes and see what they have in common.
207c³ 108c²
∧ ∧ ∧ ∧
9·23 c·c·c 9·12 c·c
∧ ∧ ∧
3·3 3·3 3·4
∧
2·2
207c³: 3·3·23 c·c·c
108c²: 2·2·3·3·3·4 c·c
GCF = 3·3 c·c
= 9c²
Answer:
C and D
Step-by-step explanation:
using the rules of exponents
A
=
≠ ![\sqrt[3]{125^7}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125%5E7%7D)
B
(
)^7 =
≠ 
C
(
)^5 =
← correct
D
(
)^9 =
← correct
Answer:
Solution given:
y=2x-5......1.
y=-3x+10.....2.
equating equation 1 &2
2x-5=-3x+10
2x+3x=10+5
x=15/5
x=3
again
y=2×3-5=1
so
<em><u>x,y=3,1 is your answer.</u></em>
Answer:
Step-by-step explanation:
<u>Coordinates given:</u>
<u>Plotted, these points give a right triangle with hypotenuse DF</u>
- Distance DE = 4 - (-3) = 7
- Distance EF = 2 - (-3) = 5
- Distance DF = √(7²+5²) = √84 = 8.6
<u>Perimeter</u>
The answer is 2,117 im pretty sure.