Answer:
 
 
Step-by-step explanation:
Let's use the definition of the Laplace transform and the identity given:![\mathcal{L}[t \cos 5t]=(-1)F'(s)](https://tex.z-dn.net/?f=%5Cmathcal%7BL%7D%5Bt%20%5Ccos%205t%5D%3D%28-1%29F%27%28s%29) with
 with ![F(s)=\mathcal{L}[\cos 5t]](https://tex.z-dn.net/?f=F%28s%29%3D%5Cmathcal%7BL%7D%5B%5Ccos%205t%5D) .
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Now,  . Using integration by parts with u=e^(-st) and dv=cos(5t), we obtain that
. Using integration by parts with u=e^(-st) and dv=cos(5t), we obtain that  .
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Using integration by parts again with u=e^(-st) and dv=sin(5t), we obtain that
  .
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Solving for F(s) on the last equation,  , then the Laplace transform we were searching is
, then the Laplace transform we were searching is  
 
 
        
             
        
        
        
Here is the answer you are looking for: (7,13/3)
Please vote my answer brainliest. thanks!
        
             
        
        
        
<h3>
Answer:  19 dimes</h3>
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Work Shown:
d = number of dimes
q = 32-d = number of quarters
$5.15 = 515 cents
10d+25q = 515
10d+25(32-d) = 515
10d+800-25d = 515
-15d+800 = 515
-15d = 515-800
-15d = -285
d = -285/(-15)
d = 19
There are 19 dimes. You can stop here if you want.
q = 32-d = 32-19 = 13
There are 13 quarters
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Check:
1 dime = 10 cents
19 dimes = 19*10 = 190 cents
1 quarter = 25 cents
13 quarters = 13*25 = 325 cents
total value = 190 cents + 325 cents = 515 cents = $5.15
The answer is confirmed.
 
        
        
        
Leslie did. If you multiply 4/5 by two, you get 8/10. 8/10 is greater than 7/10. 
        
                    
             
        
        
        
<h3>Answer:</h3>
x/tan(x) is an even function
sec(x)/x is an odd function
<h3>Explanation:</h3>
<em>x/tan(x)</em>
For f(x) = x/tan(x), consider f(-x).
... f(-x) = -x/tan(-x)
Now, we know that tan(x) is an odd function, so tan(-x) = -tan(x). Using this, we have ...
... f(-x) = -x/(-tan(x)) = x/tan(x) = f(x)
The relation f(-x) = f(x) is characteristic of an even function, one that is symmetrical about the y-axis.
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<em>sec(x)/x</em>
For g(x) = sec(x)/x, consider g(-x).
... g(-x) = sec(-x)/(-x)
Now, we know that sec(x) is an even function, so sec(-x) = sec(x). Using this, we have ...
... g(-x) = sec(x)/(-x) = -sec(x)/x = -g(x)
The relation g(-x) = -g(x) is characeristic of an odd function, one that is symmetrical about the origin.