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Ivenika [448]
3 years ago
12

Abit is planning a birthday party for his granddad. He bought a cake for $18\$18$18dollar sign, 18. He also wants to buy some ba

lloons, which are $4\$4$4dollar sign, 4 each. Abit has $35\$35$35dollar sign, 35 to spend all together. How much money will Abit have left after he buys the cake and as many balloons as possible?
Mathematics
1 answer:
Arturiano [62]3 years ago
3 0

Answer:

$1.00

Step-by-step explanation:

Total Budget = $35

Cake Spent = $18

Remaining Money = 35 - 18 = $17

Since, each balloon is worth $4, to find how many balloons he will get with remaining money ($17), we divide the the remaining money by price of each balloon:

17/4 = 4.25

We can't have fractional balloons, so Abit can get 4 balloons, MAXIMUM.

4 balloons cost = $4 per balloon * 4 = $16

So, from $17 if he spends $16 for balloons, he will have left:

$17 - $16 = $1.00

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A triangle has one side that is 5 inches long and another that is 7 inches long. How many different lengths, in inches,are possi
lubasha [3.4K]

Answer:

2 < c < 12

Step-by-step explanation:

Let the last side of the triangle = c

The sum of any two sides must be greater than the third side. Let's say we have triangle ABC, where a = 5 inches and b = 7 inches

a + b > c (1)

a + c > b (2)

b + c > a (3)

From (1);

a + b > c

7 + 5 > c

c < 12

From (2):

a + c > b

7 + c > 5

7 - 5 < c

c > 2

From (3):

b + c > a

5 + c > 7

c > 7 - 5

c > 2

So the possible lengths of c are: 2 < c < 12

3 0
3 years ago
What is the perimeter of the rectangle?<br> A 30 cm<br> B. 60 cm<br> C. 200 cm<br> D. 400 cm
Olin [163]

Answer:

60 cm

B.)60 cm

5 0
3 years ago
Read 2 more answers
Cathy rolls a number cube that is labeled from 1 to 6.
MatroZZZ [7]

Answer: 2/3

Cathy rolls a number cube that is labeled from 1 to 6.

Total outcomes = {1,2,3,4,5,6}

she rolls an even number or a multiple of 3

Outcomes of an even number = {2,4,6}

Outcomes of multiple of 3 = {3,6}

so favorable outcomes of even number or a multiple of 3 = {2,3,4,6}

Probability ( any event) =number of favorable outcomes divide by total  number of outcomes

probability(even number or a multiple of 3) = \frac{4}{6}=\frac{2}{3}

7 0
3 years ago
1. La suma de dos números es 115. El número mayor es dos veces más 22 unidades que el otro. Hallar
Lerok [7]

De acuerdo con un sistema de ecuaciones, tiene-se que los números son 31 y 84.

----------------

  • En el sistema de ecuaciones, tiene-se que los números son x e y.
  • Suma de 115, o sea, x + y = 115
  • <u>El número mayor es dos veces más 22 unidades que el otro</u>, o sea, x = 2y + 22

----------------

Primero se encuenta el número menor, <u>reemplazando la segunda ecuación en la primera:</u>

x + y = 115

2y + 22 + y = 115

3y = 93

y = \frac{93}{3}

y = 31

----------------

El número mayor es dado en <u>función de el menor</u>, o sea:

x = 2y + 22 = 2(31) + 22 = 62 + 22 = 84

Los números son 31 y 84.

Otro problema resuelto por sistema de ecuaciones es dado en brainly.com/question/24637096

6 0
3 years ago
Hello can someone help me simplify 4) and 5)? Thank you and please include steps :)
Leni [432]
Alrighty

remember some rules
(ab)^c=(a^c)(b^c)
and
x^{-m}=\frac{1}{x^m}
and
x^0=1 for all real values of x
and
(a^b)^c=a^{bc}
and
(\frac{a}{b})^c=\frac{a^c}{b^c}
and
(a/b)/(c/d)=(ad)/(bc)
and
(a^b)(a^c)=a^{b+c}
and
\frac{a^m}{a^n}=a^{m-n}
and don't forget pemdas
example: -x^m=-1(x^m) but (-x)^m=(-1)^m(x^m)

so

4.
(\frac{c^{-2}}{2})^{-2}=

\frac{(c^{-2})^{-2}}{2^{-2}}=

\frac{c^4}{\frac{1}{2^2}}=

\frac{c^4}{\frac{1}{4}}=

4c^4



5.

\frac{(-a)^4bc^5}{-a^2b^{-3}c^0}=

\frac{(-1)^4(a)^4bc^5}{-1(a^2)(\frac{1}{b^3}(1)}=

\frac{(1)a^4bc^5}{\frac{(-1)(a^2)}{b^3}}=

\frac{(a^4bc^5)b^3}{(-1)(a^2)}=

\frac{-a^4b^4c^5}{a^2}=

-a^2b^4c^5
3 0
3 years ago
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