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3 years ago

What is the surface area of this right triangular prism ? round your answer to the nearest tenth.

Mathematics

2 answers:

Anton [14]3 years ago

6 0

Answer: the surface area of the triangular prism is 78 m

Step-by-step explanation:

The surface area of the triangular prism is the sum of the area of each face of the prism.

The formula for determining the area of the triangular face is expressed as

Area = 1/2 × base × height

Area = 1/2 × 8 × 3 = 12m

Area of the 2 triangular faces is

12 × 2 = 24 m

Area of the rectangular face at the top is 5 × 3 = 15m

Area of the two rectangular faces at the top is

2 × 15 = 30m

Area of the rectangular base is

8 × 3 = 24m

Therefore, the surface area of the triangular prism is

24 + 30 + 24 = 78 m

velikii [3]3 years ago

5 0

Answer:

78 m^2 Unless I got some of the measurements wrong, kinda hard to see them.

Step-by-step explanation:

The surface area will be the sum of the area of each face. so lets see, there is the base (in this orientation) which is a 8x3 rectangle it looks like.

then two trianglular sides with both having a base of 8 and height of 3

then two "roof" pieceswhich are rectangles again, one side of 3 and the other 5.

Now we add each face up.

rectangular base = 3x8 = 24

2 triangular sides = 2(.5*8*3) = 24

2 rectangular roof pieces = 2(5*3) = 30

Now add it all up

24+24+30 = 78

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Given:

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Which type of triangle is ΔWXY by its sides.

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Using distance formula, we get

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$WY=\sqrt{\left(-5-\left(-10\right)\right)^2+\left(11-4\right)^2}=\sqrt{74}$

Now,

$WX=WY$

So, triangle is an isosceles triangles.

and,

$WX^2+WY^2=(\sqrt{74})^2+(\sqrt{74})^2$

$WX^2+WY^2=74+74$

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2 years ago

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expeople1 [14]

Answer:

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3 years ago

What is the surface area of this right triangular prism ? round your answer to the nearest tenth.​

What is the surface area of this right triangular prism ? round your answer to the nearest tenth.