Answer: x1 = 0; x2 = 5/3; x3 = 1/3
x1 + 2x2 - x3 = 3 => 2x1 + 4x2 - 2x3 = 6
2x1 + x2 - 2x3 = 1
=> 4x2 - x2 = 5
⇔ 3x2 = 5
⇔ x2 = 5/3
with x2 = 5/3, we have: x1 - x3 = 3 - 10/3 = -1/3
3x1 - 5x3 = 5 - 4.5/3 = -5/3
=> x1 = 0
x3 = 1/3
Step-by-step explanation:
Answer:
Step-by-step explanation:
1. Combine like terms
2y-7y = -5y
-5y=5
2. Divide by -5 and the answer is
Using the Pythagorean theorm,
a^2 + b^2 = C^2, where a nd b are the side lengths and c is the hypotenuse ( diagonal line)
If it was a square both sides would be the same length so we would have:
13^2 +13^2 = c^2
169 + 169 = c^2
338 = c^2
c = SQRT(338) = 18.38
18.38 is larger than the 15.26 given in the problem , so the room is not a square.
