150x^5-60x^4-119x^3+5x-6/5x-1
Distrivute 0.2 to x and +50 and you get 0.2x+10-6 now for the other side we do the same and we get 1.2x+8 or an easier way... Let's solve your equation step-by-step.<span><span><span>0.2<span>(<span>x+50</span>)</span></span>−6</span>=<span>0.4<span>(<span><span>3x</span>+20</span>)</span></span></span>Step 1: Simplify both sides of the equation.<span><span><span>0.2x</span>+4</span>=<span><span>1.2x</span>+8</span></span>Step 2: Subtract 1.2x from both sides.<span><span><span><span>0.2x</span>+4</span>−<span>1.2x</span></span>=<span><span><span>1.2x</span>+8</span>−<span>1.2x</span></span></span><span><span><span>−x</span>+4</span>=8</span>Step 3: Subtract 4 from both sides.<span><span><span><span>−x</span>+4</span>−4</span>=<span>8−4 </span></span><span><span>−x</span>=<span>4 now you divide by negative x (technically it is -1x=4 so your answer is x=-4</span></span>
Answer:
answer SHOULD be 3 sandwiches
Step-by-step explanation:
33-6=27÷9=3
Answer:
Minimum 200 people other than the 2 charity representatives.
Step-by-step explanation:
Given that:
The venue can hold a maximum of 500 people.
Cost of venue = $1000
Per person cost for food = $20
Two charity representatives get to attend the dinner for free.
To find:
The inequality and to determine how many people must come to keep costs at most $25.
Solution:
Let the number of people attending the dinner = 
Cost of food for people = 
Total cost = $1000 +
Cost per person = Total cost divided by Number of people attending the dinner.
As per question statement:
Therefore, the answer is:
Minimum 200 people other than the 2 charity representatives should attend the dinner.
Answer:
(2, 20/3)
Step-by-step explanation:
