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GrogVix [38]
3 years ago
9

Please help me with this i really dont get what it means, thank you!! xo

Mathematics
1 answer:
Tasya [4]3 years ago
5 0

i would probably say the first option. you basically want to use the 2 points that are outside of the majority of all of the other points. in this case, i am pretty sure it would be the first option. i am not 100% sure, but i think that's the correct answer :)

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C=5/9(F-32) solve for F
mina [271]
<span>F= 9/5 C + 32
      or
</span><span>F= 9/5(C+32)
</span>                          Hoped this helped:)
7 0
3 years ago
PLEASE HELPPPPP
dsp73

Answer:

see explanation

Step-by-step explanation:

the equation of parabola in vertex form is

y = a(x - h)² + k

where (h, k ) are the coordinates of the vertex and a is a multiplier.

here (h, k ) = (3, 1 ) , then

y = a(x - 3)² + 1

to find a substitute any other point on the graph into the equation.

using (0, 7 )

7 = a(0 - 3)² + 1 ( subtract 1 from both sides )

6 = a(- 3)² = 9a ( divide both sides by 9 )

\frac{6}{9} = \frac{2}{3} = a

y = \frac{2}{3} (x - 3)² + 1 ← in vertex form

------------------------------------------------------

the equation of a parabola in factored form is

y = a(x - a)(x - b)

where a, b are the zeros and a is a multiplier

here zeros are - 1 and 3 , the factors are

(x - (- 1) ) and (x - 3), that is (x + 1) and (x - 3)

y = a(x + 1)(x - 3)

to find a substitute any other point that lies on the graph into the equation.

using (0, - 3 )

- 3 = a(0 + 1)(0 - 3) = a(1)(- 3) = - 3a ( divide both sides by - 3 )

1 = a

y = (x + 1)(x - 3) ← in factored form

3 0
2 years ago
Help me pls thank you
Marianna [84]

Answer:

More than half the students scored 81 or better on the test

There were 12 students who scored 80 on the test

The same number of students scored between 81 and 90 on the test as scored between 61 and 80.

Step-by-step explanation: Please think this through, I don't know if I'm correct. It is either all or one of these

7 0
2 years ago
A.
Reptile [31]

Answer:

The real zeros of f(x) are x = 0.3 and x = -3.3.

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

In this problem, we have that:

f(x) = x^{2} + 3x - 1

So

a = 1, b = 3, c = -1

\bigtriangleup = 3^{2} - 4*1*(-1) = 13

x_{1} = \frac{-3 + \sqrt{13}}{2*1} = 0.3

x_{2} = \frac{-3 - \sqrt{13}}{2*1} = -3.3

The real zeros of f(x) are x = 0.3 and x = -3.3.

7 0
3 years ago
Sketch the plane representing -2x²=-8
stellarik [79]

I found this answer from Brainly.

Somebody else did this question.

**But it's not my answer**

I hope it's helpful and correct!!

7 0
3 years ago
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