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torisob [31]
3 years ago
15

Find the equivalent to x^7

Mathematics
1 answer:
MrMuchimi3 years ago
3 0
1/x^-7

It would look more like       1
                                        ------
                                             -7 (as an exponent)
                                          x
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Find value of X, please !!
Drupady [299]

Answer:

x=25

Step-by-step explanation:

60+70=130

180-130=50

50/2=25

4 0
3 years ago
Read 2 more answers
Compare the line passing through the points (−3, −11) and (6, 4) to the line given by the equation y=35x−6.
Aleks04 [339]
Let
<span>A------> (−3, −11)
B------>  (6, 4)

step 1
find the slope m point A and point B
m=(y2-y1)/(x2-x1)-----> </span>m=(4+11)/(6+3)----> m=15/9---> 5/3

step 2
with m=5/3 and point B (6, 4)  find the equation of a line
y-y1=m*(x-x1)-----> y-4=(5/3)*(x-6)---> y=(5/3)x-6

case <span>a. they have the same slope------> is not correct
because
</span><span>y=35x−6------> the slope m=35
</span>y=(5/3)x-6---> the slope m =5/3

case <span>b. they have the same x-intercept.----> is not correct
because
</span>the x-intercept is for y=0

y=35x−6-----> 0=35x-6----> 35x=6-----> x=6/35
the x-intercept is the point (6/35,0)

y=(5/3)x-6----> 0=(5/3)x-6----> (5/3)x=6---> x=18/5
the x-intercept is the point (18/5,0)

case <span>c. the two lines are perpendicular. do. they have the same y-intercept-----> is nor correct
because

if two lines are perpendicular
m1*m2=-1-------> </span><span>this condition is not satisfied
</span>
the y intercept is for x=0

y=35x−6-------> y=-6
the y intercept is the point (0,-6)

y=(5/3)x-6-----> y=-6
the y intercept is the point (0,-6)

 they have the same y-intercept but the two lines are not perpendicular

see the attached figure

7 0
3 years ago
What will my solution be 9 8 8 2345
stepan [7]

Answer:

9882345=9.882345 X 10^{6}

Step-by-step explanation:

3 0
2 years ago
What is the range of data?
a_sh-v [17]

Answer:

The range of data is 9

Step-by-step explanation:

We know that

range of data = maximum value of data - minimum value of data

Now, we can find maximum value of data

and minimum value of data

so,

maximum value of data =9

minimum value of data =0

now, we can plug these values

and we get

range of data =9-0

range of data =9

6 0
3 years ago
Consider the expression 2√3 cos(x)csc(x)+4cos(x)-3csc(x)-2 √ 3 This expression can be represented as the product of the factors.
Alla [95]

Answer with explanation:

The given expression is:

 2 \sqrt{3}\cos x * \csc x+4 \cos x-3 \csc x-2\sqrt{3}\\\\=2 \cos x*(\sqrt{3}*\csc x+2)-\sqrt{3}*(\sqrt{3}*\csc x+2)\\\\\rightarrow (2\cos x -\sqrt{3})*(\sqrt{3}*\csc x+2)\\\\\rightarrow (2\cos x -\sqrt{3})*(\sqrt{3}*\csc x+2)=0\\\\(2\cos x -\sqrt{3})=0 \wedge (\sqrt{3}*\csc x+2)=0

  \cos x=\frac{\sqrt{3}}{2} \wedge \csc x=\frac{-2}{\sqrt{3}}\\\\x=\frac{\pi}{6},2\pi-\frac{\pi}{6}\\\\x=\frac{\pi}{6},\frac{11\pi}{6} \wedge x=\pi+\frac{\pi}{3} ,2\pi-\frac{\pi}{3}\\\\x=\frac{4\pi}{3},\frac{5\pi}{3}\\\\x={\frac{\pi}{6},\frac{11\pi}{6},\frac{4\pi}{3},\frac{5\pi}{3}}

Option C

8 0
2 years ago
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