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hichkok12 [17]
2 years ago
5

Can you plz help me real quick I want good grades so I don't disappoint ​

Mathematics
1 answer:
Goshia [24]2 years ago
4 0

Answer:

x= 6

∠FGT = 55

∠GFE = 65

Step-by-step explanation:

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Rhombus ABCD is shown below with diagonals Line BD and AC interesting at Point E such that m
notka56 [123]

io sai meu srapza,bel a mlaandro

8 0
3 years ago
Question 18
Svetlanka [38]

Answer:

Step-by-step explanation:

J and K are equal

8x - 23 = 6x + 11            Add 23 to both sides

8x = 6x + 11 + 23           Combine the right

8x = 6x + 34                  Subtract 6x from both sides

8x - 6x = 34                   Combine the left

2x = 34                           Divide by 2

x = 34/2

x = 17

=================================

M and L are both supplementary to J and K respectively.

J = 8x - 23

J = 8*17 - 23

J = 136-23

J = 113

K = 113

===================================

M + 113 = 180

M = 180 - 113

M = 67

L = 67

5 0
2 years ago
Can someone solve this its probably easy but i dont know
Rzqust [24]

Answer:

Step-by-step explanation:

A={26,30,32,44,48}

B={22,26,34}

A∩B=26

number of elements=1

elements in ξ are {22,24,26,28,30,32,34,36,38,40,42,44,46,48}

number of elements  in ξ=14

P(A∩B)=1/14

I can't draw venn diagram but i give hint

A={30,32,44,48}+{26}

B={22,34}+{26}

A∩B={26}

6 0
3 years ago
Express the rate 50 yards per minute in feet per second. Please answer with supporting work.
DiKsa [7]
First, multiply 50*3 to get the answer in feet which is 150 ft.

Then, divide 150 ft by 60 which would be 2.5 ft per second.
3 0
3 years ago
A certain math teachers likes to keep a box of prizes to distribute to students. The math teacher likes to keep at least twice a
Law Incorporation [45]

Option C

Math teacher would need to buy 130 prizes

<em><u>Solution:</u></em>

Given that,

Math teacher currently has 109 students and the box has 88 prizes in it

The math teacher likes to keep at least twice as many prizes in the box as she has students

So, she wants the number of prizes to be twice the number of students

Therefore,

number of prizes = 2 x 109 students

number of prizes = 2 x 109 = 218 prizes

The box has 88 prizes in it

Therefore, number of prizes she would need to buy is:

⇒ 218 - 88 = 130

Thus she would need to buy 130 prizes

3 0
2 years ago
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