All categories

4 years ago

Please help

Mathematics

1 answer:

Vlada [557]4 years ago

4 0

We know that

When we have

$f(x)=ax^2 +bx+c$

Here ,

a is the leading coefficient

c is the constant term

so, we can compare it with

$f(x)=5x^2-7x+6$

so, we get

$a=5,c=6$

so,

leading coefficient is 5

constant term is 6......................Answer

You might be interested in

HELP ME LLEASE WUIZ OMG WHAT ARE THE CORDS? 30 points

wariber [46]

Answer: -1/2 and 1/3

Step-by-step explanation:

3 0

3 years ago

4. Break-Even Analysis

DiKsa [7]

Answer:

x = 1178 games

Step-by-step explanation:

Let the number of games = x

Let the total cost = Tc

Let the total revenue = Tr

Given the following data;

Investment = $10,000

Cost of each game = $1.50

Selling cost = $9.99

Total cost, Tc = (Cost of each game * Number of games) + Investment

Tc = 1.50x + 10000

Total revenue, Tr = Selling cost * Number of games

Tr = 9.99x

Breakeven point is when total cost is equal to total revenue;

Tc = Tr

$1.50x + 10000 = 9.99x$

$9.99x - 1.50x = 10000$

$8.49x = 10000$

$x = \frac {10000}{8.49}$

x = 1177.86 ≈ 1178 games.

<em>Therefore, the number of games that must be sold before the business breaks even is 1178 games. </em>

4 0

3 years ago

A company that manufactures cell phones has done research to determine how the pricing of thier phones affects how many they sel

pantera1 [17]

B.Less than $200 or more than $500

6 0

3 years ago

Two times the sum of a number and three is not equal to eight

jarptica [38.1K]

Could be the sum is 1 and then 2 times 2 which equals 4 then 5 then plus 3 it is 8 so wrong

8 0

3 years ago

The angle of elevation of the top of a pole as seen from a point 13 ft away from the base is double its angle of elevation as se

spayn [35]

The height of the pole above the level of the observer's eyes is 31.42 ft

Let the angle of elevation of the top of the pole from a point 47 ft away be α.

Let the angle of elevation of the top of the pole from the point 13 ft away be β.

Since the angle of elevation of a point 13 feet away is twice that from 47 ft away, we have that β = 2α.

If the height of the pole above the level of the observer's eye is h, we have that

tanβ = tan2α = h/13 and tanα = h/47

From trigonometric identities tan2α = 2tanα/(1 - tan²α)

Substituting the values of the variables into the equation, we have

tan2α = 2tanα/(1 - tan²α)

h/13 = 2h/47 ÷ [1 - (h/47)²]

Dividing through by h, we have

1/13 = 2/47 ÷ [1 - (h/47)²]

Cross-multiplying, we have

1/13 = 2/47 ÷ [1 - (h/47)²]

1 - (h/47)² = 2/47 × 13

1 - (h/47)² = 26/47

(h/47)² = 1 - 26/47

(h/47)² = (47 - 26)/47

(h/47)² = 21/47

Taking square-root of both sides, we have

h/47 = √(21/47)

Cross-multiplyng, we have

h = √(21/47) × 47

h = √(21 × 47)

h = √987

h = 31.42 ft

The height of the pole above the level of the observer's eyes is 31.42 ft

Learn more about height of a pole here:

brainly.com/question/10375496

4 0

2 years ago