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Monica [59]
3 years ago
6

What is 188.8 rounded to the nearest hundredth

Mathematics
1 answer:
My name is Ann [436]3 years ago
7 0

Answer:

188.80 to the nearest hundredth

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Please help ill give you 50 points
Verdich [7]

a. 3 × 10^0

b. 33. 6 × 10^0

c. 57. 6 × 10^2

d. 4. 0 × 10^-7

e. 7. 0 × 10^-1

<h3>What is scientific notation?</h3>

Scientific notation is simply a way of expressing numbers that are too large or small to be written in decimal form.

It may be referred to as standard index form or scientific form.

From the information given, we have;

a. 0. 000003 is written in standard form as;

= 3 × 10^-6 × 3 × 10^6

= 3 × 10^-6 + 3

= 3 × 10^0

= 3

b. 56, 000, 000. 00 is written in standard form as;

= 5. 6 × 10^7 × 6 × 10^-7

= 33. 6 × 10^7 -7

= 33. 6 × 10^0

= 33. 6

c. 8. 0 × 10^-3 × 7. 2 × 10^5

= 57. 6 × 10^-3 + 5

= 57. 6 × 10^2

d. 4. 0 × 10^-3 × 4. 0 × 10^-4

= 4. 0 ^ -3 +(-4)

= 4. 0 × 10^-7

e. 7. 0 × 10^3 × 7. 0 × 10^4

= 7. 0 × 10^ 3-4

= 7. 0 × 10^-1

Thus, scientific notation is also referred to as standard form.

Learn more about scientific notation here:

brainly.com/question/27862246

#SPJ1

5 0
1 year ago
Joe has one book each for algebra, geometry, history, psychology, Spanish, English and Physics in his locker. How many different
Alisiya [41]

Answer:

There are 35 different sets of 3 books Joe could choose

Step-by-step explanation:

* Lets explain how to solve the problem

- Combination is a collection of the objects where the order doesn't

 matter

- The formula for the number of possible combinations of r objects from

 a set of n objects is nCr = n!/r!(n-r)!

- n! = n(n - 1)(n - 2)................. × 1

Lets solve the problem

- Joe has one book each for algebra, geometry, history, psychology,

 Spanish, English and Physics in his locker

∴ He has <em>seven</em> books in the locker

- He wants to chose <em>three</em> of them

∵ The order is not important when he chose the books

∴ We will use the combination <em>nCr</em> to find how many different sets

  of three books he can choose

- The total number of books is 7

∴ n = 7

∵ He chooses 3 of them

∴ r = 3

∵ 7C3 = 7!/3!(7 - 3)! = 7!/3!(4!)

∴ 7C3=\frac{(7)(6)(5)(4)(3)(2)(1)}{[(3)(2)(1)][(4)(3)(2)(1)]}=35

∴ 7C3 = 35

* There are 35 different sets of 3 books Joe could choose

3 0
3 years ago
Send the answer for this and explain i dont get it
r-ruslan [8.4K]
The entire thing or just a specific part such as the letter?
8 0
2 years ago
Explain the steps you would take to complete this conversion problem. 406lb/1 × 1kg/2.2lb × 1,000g/1kg
alexandr402 [8]

The question was not written correctly

Correct Question

Explain the steps you would take to complete this conversion problem. 406lb/1000g × 1kg/2.2lb × 1,000g/1kg

Answer:

184.159kg

Step-by-step explanation:

From the conversion given above

We can see that we are trying to convert 406lbs to kg

1 kg = 1000gram

1 kg = 22lb

Hence,

406lb/1000g× 1kg/2.2lb × 1,000g/1kg

= 184.159kg

5 0
3 years ago
Read 3 more answers
Simplify 5+4<br> (3+4÷(11-7))
padilas [110]

Answer: the answer is 81

Step-by-step explanation:

5+4(3+4÷(11-7))

This is BODMAS rule

so, first complete the brackets B

so, 5+4(3+4(4))

     = 5+4(3+16)

     5+4 x 19

      = 5+ 76

      = 81

6 0
3 years ago
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