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Mariana [72]
3 years ago
11

Elisa withdrew $20 at a time from her bank account and withdrew a total of $140. Francis with $45 at a time from his bank accoun

t and withdrew a total of $270. Who made the greater number of withdraws?
Mathematics
1 answer:
murzikaleks [220]3 years ago
7 0
Elisa made 7 withdraws and Francis made 6.
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Evaluate the algebraic<br> expression:<br> Plz answer quick
Andrew [12]

Answer:

7,-5,-11

Step-by-step explanation:

-3(-4)-5=7

-3(0)-5=-5

-3(2)-5=-11

5 0
3 years ago
Answer number one please
tankabanditka [31]

Answer:

-3 + 6 = -3

Step-by-step explanation:

add the terms -3 and 6

exponent law

6 0
3 years ago
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I provided it in the picture, please help!
Goshia [24]
The answer would be D.
7 0
3 years ago
Credit sales are collected as follows:65 percent in the month of the sale.25 percent in the month after the sale.10 percent in t
Vitek1552 [10]

Answer:

Step-by-step explanation:

a) November sales = (Total Uncollected Sales - Uncollected Sales from December) / Collection rate after two months

= ($121,100 - $87,300) / 0.20

November sales = $169, 000.00

b) December sales = Uncollected sales from December / Collection rate of the previous month sales,

Therefore: December sales = $87,300 / 0.45 = $194,000

December sales = $194,000.00

c) Each month's collection for the company are:

Collections for ech month = 0.20(Sales from 2 months ago) + 0.25(Last month's sales) + 0.55 (Current sales)

January collections = 0.20($169000.00) + 0.25($194,000.00) + 0.55($132,000)

January collections = $154,900.00

February collections = 0.20($194,000.00) + 0.25($132,000) + 0.55($149,000)

February collections = $153,750.00

March collections = 0.20($132,000) + 0.25($149,000) + 0.55($164,000)

March collections = $153,850.00

4 0
4 years ago
If SAT scores are normally distributed with a mean of 1518 and a standard deviation of 325, find the probability that a randomly
aliya0001 [1]
Mean, x_bar = 1518
Standard deviation, sigma = 325
Range required: 1550 ≤ X ≤ 1575

Z = (X - x_bar)/sigma

Z1 = (1550-1518)/325 ≈ 0.1
Z2 = (1575-1518)/325 ≈ 0.18

From Z tables,
P(Z1) = 0.5398
P(Z2) = 0.5714

P(1550≤X≤1575) = P(Z2) - P(Z1) = 0.5714 - 0.5398 = 0.0316

The correct answer is C.
3 0
3 years ago
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