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Evgesh-ka [11]
3 years ago
14

Evaluate the algebraic expression: Plz answer quick

Mathematics
1 answer:
Andrew [12]3 years ago
5 0

Answer:

7,-5,-11

Step-by-step explanation:

-3(-4)-5=7

-3(0)-5=-5

-3(2)-5=-11

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Write an equation of the line that passes through the point (4, –5) with slope 2.
Jlenok [28]

Answer:

y + 5 = 2(x−4)

Step-by-step explanation:

slope = 2

y = mx + b

-5 = 2(4) + b

-5 = 8 + b

-8    -8

------------------

-13 = b

y = 2x - 13, in other words --> y + 5 = 2(x−4)

So, y + 5 = 2(x − 4) is the equation of the line that passes through (4, -5).

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What do 5/15 + 3/5 equal
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14/15


5/15 + (3x3 / 3x5) = 5/15 + 9/15 = 14/25
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(-6,-3) (6,-7) enter your answer in slope intercept form
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The values of the slope and y-intercept are m=Undefined m=Undefined and (Undefined)⋅(6)+b=−3(Undefined)⋅(6)+b=-3

Undefined

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The number of times that students go to the movies per year has mean is a normal distribution with a mean of 17 with standard de
antiseptic1488 [7]

Answer:

53.84% probability that for a group of 10 students, the mean number of times they go to the movies each year is between 14 and 18 times.

Step-by-step explanation:

To solve this problem, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a sample of size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 17, \sigma = 8, n = 10, s = \frac{8}{\sqrt{10}} = 2.53

What is the probability that for a group of 10 students, the mean number of times they go to the movies each year is between 14 and 18 times?

This probability is the pvalue of Z when X = 18 subtracted by the pvalue of Z when X = 14. So

X = 18

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{18 - 17}{2.53}

Z = 0.4

Z = 0.4 has a pvalue of 0.6554

X = 14

Z = \frac{X - \mu}{s}

Z = \frac{14 - 17}{2.53}

Z = -1.19

Z = -1.19 has a pvalue of 0.1170

0.6554 - 0.1170 = 0.5384

53.84% probability that for a group of 10 students, the mean number of times they go to the movies each year is between 14 and 18 times.

3 0
3 years ago
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