Yes I sure did hang the picture what about it
Given two points A(x₁,y₁) and B(x₂,y₂) the distance betwen these points will be:
dist(A,B)=√[(x₂-x₁)²+(y₂-y₁)²].
We have these points: A(0,0) and B(6,3); its distance will be:
dist(A,B)=√[(6-0)²+(3-0)²]
=√(6²+3²)
=√(36+9)
=√45 ≈ 6.71
Answer: D. 6.71 units.
(2/7)^2 x (7/9)^2
((2^2)/(7^2)) x ((7^2)/(9^2))
(4/49) x (49/81)
*Cross multiply*
(4/81)
Answer:
134 children and 120 adult plates were served
Step-by-step explanation:
let the children mean be x
Let the adult meal be y
If fourteen less children’s meals were served than adult meals at a barbecue, then;
y = x - 14 .... 1
IF Children plate were 1.50 each and adult plates were 2.00 each with a total of 441 in amount then;
1.5x + 2y = 441 .... 2
Substitute 1 into 2;
1.5x + 2(x-14) = 441
1.5x+2x-28 = 441
3.5x = 441+28
3.5x = 469
x = 469/3.5
x = 134
Recall that y = x - 14
y = 134-14
y = 120
Hence 134 children and 120 adult plates were served