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Romashka [77]
3 years ago
10

HELP I NEED HELP ASAP

Mathematics
2 answers:
hram777 [196]3 years ago
8 0
I think the answer to that question is C
lozanna [386]3 years ago
5 0

Answer:

The answer is C.

Step-by-step explanation:

:)

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Z=<br><br> 37 <br><br> 51 <br><br> 39<br><br> Triangles and Trigonometry
san4es73 [151]

Answer:

z =  { \tan( \frac{10}{8} ) }^{ - 1}  \\ z =(51.34019174591)

So the corect answer is (51)

5 0
3 years ago
Abed says he has written a system of two linear equations that has an infinite number of solutions. One of the equations of the
LenKa [72]

Answer:

3x - y = 1

Step-by-step explanation:

This will be the same equation written in a different way'

The original equation is:

y = 3x - 1

0 = 3x - y - 1

3x - y = 1.

3 0
3 years ago
Which answer choice represents an equivalent number sentence of "49 - 12"?
Dahasolnce [82]

Answer:

B

Step-by-step explanation:

A. 37 isn't a number sentence

B. 49 + (-12) = 49-12. They're the same thing  because 49 minus 12 can also be written as 49 plus negative 12

C. 49 + 12 doesn't equal 49-12

D. 12- 49 = -37 which isn't equivalent to 49-12.

Hope this helps!!!

6 0
3 years ago
Read 2 more answers
What is the correct scientific notation for these two questions?
UNO [17]

Answer:

The image is blurry on my screen

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
A professor has learned that three students in his class of 20 will cheat on the final exam. He decides to focus his attention o
balu736 [363]

Answer:

a

P(X \ge 1) = 0.509

b

P(X  \ge 1) = 0.6807

Step-by-step explanation:

From the question we are told that

   The number of students in the class is  N  =  20  (This is the population )

   The number of student that will cheat is  k =  3

   The number of students that he is focused on is  n  =  4

Generally the probability distribution that defines this question is the  Hyper geometrically distributed because four students are focused on without replacing them in the class (i.e in the generally population) and population contains exactly three student that will cheat.

Generally  probability mass function is mathematically represented as

      P(X = x) =  \frac{^{k}C_x * ^{N-k}C_{n-x}}{^{N}C_n}

Here C stands for combination , hence we will be making use of the combination functionality in our calculators  

Generally the that  he finds at least one of the students cheating when he focus his attention on four randomly chosen students during the exam is mathematically represented as

      P(X \ge 1) =  1 - P(X \le 0)

Here  

   P(X \le 0) =  \frac{ ^{3} C_0 *  ^{20 - 3} C_{4- 0}}{ ^{20}C_4}

   P(X \le 0) =  \frac{ ^{3} C_0 *  ^{17} C_{4}}{ ^{20}C_4}

   P(X \le 0) =  \frac{ 1 *  2380}{ 4845}

    P(X \le 0) =  0.491

Hence

    P(X \ge 1) =  1 - 0.491

     P(X \ge 1) = 0.509

Generally the that  he finds at least one of the students cheating when he focus his attention on six randomly chosen students during the exam is mathematically represented as

    P(X \ge 1) =  1 - P(X \le 0)

   P(X  \ge 1) =1- [  \frac{^{k}C_x * ^{N-k}C_{n-x}}{^{N}C_n}]

Here n =  6

So

    P(X  \ge 1) =1- [  \frac{^{3}C_0 * ^{20 -3}C_{6-0}}{^{20}C_6}]

    P(X  \ge 1) =1- [  \frac{^{3}C_0 * ^{17}C_{6}}{^{20}C_6}]

    P(X  \ge 1) =1- [  \frac{1  *  12376}{38760}]

    P(X  \ge 1) =1- 0.3193

    P(X  \ge 1) = 0.6807

   

5 0
3 years ago
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