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Ann [662]
2 years ago
14

On a given day, the coldest surface temperature on the Moon, $-280$°F, is $53.6$°F colder than twice the coldest surface tempera

ture on Earth. What is the coldest surface temperature on Earth that day?
The coldest temperature is

°F.

Question 2

Justify your answer.
please help me it's due today
Mathematics
2 answers:
Vlada [557]2 years ago
8 0

Answer:

-280 = 2X-53.6

We can add 53.6 in both sides and we got:

-280 +53.6 = 2X

And now we can divide both sides by 2 and we got:

X= \frac{-226.4 F}{2}= -113.2F

Step-by-step explanation:

For this case we know the following info:

T_{min}= -280 F represent the coldest temperature in the Moon

X represent the minimum temperature of Earth

And we know the following relation :"the coldest surface temperature on the Moon, $-280$°F, is $53.6$°F colder than twice the coldest surface temperature on Earth", so we can write this like that:

-280 = 2X-53.6

We can add 53.6 in both sides and we got:

-280 +53.6 = 2X

And now we can divide both sides by 2 and we got:

X= \frac{-226.4 F}{2}= -113.2F

ale4655 [162]2 years ago
7 0
1.)Convert Into Equation: -280=2x-53.6
2.)Simplify: -226.4=2x
3.)Isolate X: x=-113.2

X=-113.2
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Answer:

D. Collinear

Step-by-step explanation:

Three points lying on a line are collinear because they share the same line.

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2 years ago
Is anybody able to help me get number ten? (Geometry)
Nikitich [7]

Answer:

Aha..our nemesis problem. :)

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Step-by-step explanation:

First, use a 30-60-90 triagle to find the apothem.

5\sqrt{3} =8.66\\8.66*5=43.30\\43.30/2=21.65\\

That is the area of 1 triangle. There are 6 of them in a hexagon, so multiply that number by 6:

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6 0
3 years ago
Location is known to affect the number, of a particular item, sold by an auto parts facility. Two different locations, A and B,
Mama L [17]

We have two samples, A and B, so we need to construct a 2 Samp T Int using this formula:

  • \displaystyle \overline {x}_1 - \overline {x}_2 \ \pm \ t^{*} \sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2}  }  

In order to use t*, we need to check conditions for using a t-distribution first.

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<u>Since 2/3 conditions aren't met, we can still proceed with the problem but keep in mind that the results will not be as accurate until more data is collected or more information is given in the problem.</u>

<u>Solve for t*:</u>

<u></u>

We need the <u>tail area </u>first.

  • \displaystyle \frac{1-.9}{2}= .05

Next we need the <u>degree of freedom</u>.

The degree of freedom can be found by subtracting the degree of freedom for A and B.

The general formula is df = n - 1.

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Use a calculator or a t-table to find the corresponding <u>t-score for df = 5 and tail area = .05</u>.

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Now we can use the formula at the very top to construct a confidence interval for two sample means.

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  • s_B=2
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Substitute the variables into the formula: \displaystyle \overline {x}_1 - \overline {x}_2 \ \pm \ t^{*} \sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2}  }.

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If we want to <u>interpret</u> the confidence interval of (-20.5707, -11.4293), we can say...

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5 0
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mel-nik [20]
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