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Vesnalui [34]
3 years ago
11

Simplify: (x2 − 8x + 5) + (−3x2 + 5x − 9)

Mathematics
1 answer:
tekilochka [14]3 years ago
6 0

Combine like terms (those with same number of variables)


x² + (-3x²) = -x²

-8x + 5x = -3x

5 - 9 = -4


-x² - 3x - 4 is your answer



hope this helps

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2x³-8=0<br> How do I solve this problem ?
wlad13 [49]

Answer:

x=2^{\frac{2}{3}}

Step-by-step explanation:

1) Add 8 to both sides.

<em />2x^3=8

2) Divide both sides by 2.

x^3=\frac{8}{2}

3) Simplify \frac{8}{2} to 4.

x^3=4

4) Take the cube root of both sides.

x=\sqrt[3]{4}

5) Rewrite 4 as 2².

x=\sqrt[3]{2^2}

6) Use this rule: {({x}^{a})}^{b}={x}^{ab}.

x=2^{\frac{2}{3}}

Decimal Form: 1.587401

__________________________________________

Check the answer:

2x^3-8=0

1) Let x=2^\frac{2}{3}.

2(2^{\frac{2}{3} })-8=0

2) Use this rule: (x^a)^b=x^{ab}.

2\times2^{\frac{2\times3}{3} } -8=0

3) Simplify 2 * 3 to 6.

2\times2^{\frac{6}{3} } - 8  =0

4) Simplify 6/3 to 2.

2\times2^2-8=0

5) Use Product Rule: x^ax^b=x^{a+b}.

2^3-8=0

6) Simplify 2^3 to 8.

8 - 8 = 0

7) Simplify 8 - 8 to 0.

0 = 0

Thank you,

Eddie

5 0
2 years ago
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Answer:

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Step-by-step explanation:

According to Pythagoras,

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x^2 = 19^2 - 12^2

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x^2 = 217

x = \sqrt{217}

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5 0
3 years ago
If 24, x, and 6 form the first three terms of an arithmetic sequence
AveGali [126]
<h3>Answer:  15</h3>

===============================================

Work Shown:

d = common difference

p = first term = 24

q = second term = a+d = 24+d

r = third term = q+d = 24+d+d = 24+2d = 6

------------

Solve for d

24+2d = 6

2d = 6-24

2d = -18

d = -18/2

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We add -9 to each term to get the next term. This is the same as subtracting 9 from each term to get the next term.

------------

First term = 24

Second term = 24-9 = 15

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We get the sequence 24, 15, 6

7 0
3 years ago
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Paraphin [41]
The equation would be ' y = 1/2x'
The photo of my working will be attached.

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liq [111]

Answer:

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Divide both sides by 1.54

x = 45

8 0
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