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Alex73 [517]
2 years ago
8

4x − 30 = ≤12 solve the inequality.

Mathematics
2 answers:
VMariaS [17]2 years ago
5 0
The answer is x≤10.5
mafiozo [28]2 years ago
4 0

Answer:

4x − 30 = ≤12

Step-by-step explanation:

4x − 30 = ≤12

+30 on both sides

4x≤42

divided by 4 on both sides

x≤10.5

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Find the volume of the prism in terms of y.
pogonyaev

is there a value to y? if not, this is what I got:

Y^2 + 2y + 3

7 0
2 years ago
What is the axis of symmetry of the function f(x) = –(x + 9)(x – 21)?
ludmilkaskok [199]
First, we have to realize that this is factored form, so we have to put this in standard quadratic form using FOIL, which is a rule mandating how we multiply the numbers here. F stands for First, which means the first number inside the parentheses for both of them, then O means the first number in the first quantity(fancy word for parentheses) multiplied by the last number of the second quantity, and so forth. When you are done, you combine like terms

anyway, you end up with x²-12x-189, but you have to inverse all numbers because of the parentheses in front, so it becomes -x²+12x+189.

Now you can find the axis of symmetry uisng the equation -b=2a (oh yeah, I forgot to mention: the standard quadratic form is a(x)²+b(x)+c already). So you do -12 / -2, which then becomes 6.

The axis of symmetry is 6
3 0
3 years ago
Connecticut families were asked how much they spent weekly on groceries. Using the following data, construct and interpret a 95%
Amanda [17]

Answer:

The 95% confidence interval for the population mean amount spent on groceries by Connecticut families is ($73.20, $280.21).

Step-by-step explanation:

The data for the amount of money spent weekly on groceries is as follows:

S = {210, 23, 350, 112, 27, 175, 275, 50, 95, 450}

<em>n</em> = 10

Compute the sample mean and sample standard deviation:

\bar x =\frac{1}{n}\cdot\sum X=\frac{ 1767 }{ 10 }= 176.7

s= \sqrt{ \frac{ \sum{\left(x_i - \overline{x}\right)^2 }}{n-1} }       = \sqrt{ \frac{ 188448.1 }{ 10 - 1} } \approx 144.702

It is assumed that the data come from a normal distribution.

Since the population standard deviation is not known, use a <em>t</em> confidence interval.

The critical value of <em>t</em> for 95% confidence level and degrees of freedom = n - 1 = 10 - 1 = 9 is:

t_{\alpha/2, (n-1)}=t_{0.05/2, (10-1)}=t_{0.025, 9}=2.262

*Use a <em>t</em>-table.

Compute the 95% confidence interval for the population mean amount spent on groceries by Connecticut families as follows:

CI=\bar x\pm t_{\alpha/2, (n-1)}\cdot\ \frac{s}{\sqrt{n}}

     =176.7\pm 2.262\cdot\ \frac{144.702}{\sqrt{10}}\\\\=176.7\pm 103.5064\\\\=(73.1936, 280.2064)\\\\\approx (73.20, 280.21)

Thus, the 95% confidence interval for the population mean amount spent on groceries by Connecticut families is ($73.20, $280.21).

7 0
3 years ago
SOMEONE PLS HELP ME I REALLY NEED THIS
creativ13 [48]
I’m thinking it’s A cause the others don’t seem right
3 0
2 years ago
Read 2 more answers
I need help please.
Rainbow [258]
The answer should be C
54*30/100= 16.2
54-16.2 = 37.80
4 0
3 years ago
Read 2 more answers
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