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spayn [35]
3 years ago
11

What method can be used to prove the triangles below are congruent

Mathematics
2 answers:
Neko [114]3 years ago
7 0

Answer:

<h2>SSS?</h2>

Step-by-step explanation:

I don't know why the answers don't offer this an option. However, the side that shares both triangles must be congruent to itself and the other highlighted congruent parts are sides, not angles. Therefore by my calculations, the answer has to be SSS, but this isn't a choice.

<h2>Please let me know if you need more help :)</h2>
nydimaria [60]3 years ago
7 0

Answer:

A. SAS

Step-by-step explanation:

because it is the "<u>Correct Answer</u>"

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Two boats start their journey from the same point A and travel along directions AC and AD, as shown below
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Answer:

a

Step-by-step explanation:

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F(x)=x^2-2.g(x)=4x-2
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Answer:

Step-by-step explanation:

f(x) = x²-2

g(x) = 4x-2

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2 years ago
Find the amount of the annuity due. Round to the nearest cent.
Ber [7]
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2 years ago
Solve −4 = −(−k − 86)+10
kvasek [131]
K= 100
 
You use distributive property 
<span>
Step 1: </span><span>−(−k)−1(−86)+10=−4

Step 2: </span><span>k−1(−86)+10=−4

Step 3: </span><span>k+86+10=−4

Step 4: </span><span>k+96=−4

Step 5:  </span><span>k=−96−4

Step 6:  </span><span>Subtract </span>4<span> from </span><span>−96</span><span> to get </span><span><span><span>−100</span>.</span></span>
3 0
3 years ago
Read 2 more answers
Part A
Nitella [24]

Answer:

P = 300

r = 0.15

n = 12

A(t) = 300(1.0125)^12t

Step-by-step explanation:

Given that:

Total credit taken for book purchase = $300

Annual Interest rate = 15% compounded monthly

Time or period = 4 years

P(1 + r/n)^nt

P in the expression above means the principal amount which is the total credit spent on book purchase = $300

r = annual interest rate on Emma's account = 15% = 15/100 = 0.15

n = number of compounding times per period ; loan which compounds monthly = number of months in a year = 12

Hence,

P = $300 ; r = 0.15 ; n = 12

Substituting into the equation :

P(1 + r/n)^nt

Simplified expression written in terms of t:

Final amount, A after t years

A(t) = 300(1 + 0.15/12)^12t

A(t) = 300(1 + 0.0125)^12t

A(t) = 300(1.0125)^12t

3 0
3 years ago
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