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olchik [2.2K]
3 years ago
5

Help I have a lot to do

Mathematics
1 answer:
BaLLatris [955]3 years ago
4 0
12)
(intro) Slope is change in y divided by change in x (axes). Here, the y axis is depth and the x axis is hours. So, the slope is change in depth between any two points, divided by the change in hours between the same points. The slope of this line is half a foot depth divided by 2 hours.
a) So, the slope is 0.5 / 2 = 0.25, or 1/4.
b) The graph shows a constant rate of change because the line is straight (it increases at the same speed. If the line was curving, it would not be a constant rate of change).
c) Yes, because the line has a constant rate of change now.
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A restaurant manager collected data on the number of customers in a party in the restaurant and the time elapsed until the party
Stella [2.4K]

Answer:

Option C The parties with a larger number of customers are associated with the longer times elapsed until the party left the restaurant.

Step-by-step explanation:

The correlation coefficient 0.78 shows that positive association between two variables number of customers and elapsed time until party left restaurant.

The positive association means that as the number of customers in a party increases the elapsed time also increase. So, we can say that the parties with a larger number of customers are associated with the longer times elapsed until the party left the restaurant.

4 0
3 years ago
E Question 18/20 < > NEXT DOOKMARK 18 You go out to eat and your bill is $14.76. You want to tip 20%, what will you leave
Ann [662]
$2.95 is the answer to question e
8 0
3 years ago
PLEASE HELP ASAP!!
balu736 [363]

Answer:219

Step-by-step explanation:

4 0
3 years ago
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What is the measure of x 100
Phoenix [80]

Answer:

don't understand

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6 0
2 years ago
The position of an object moving horizontally after t seconds is given by the function s equals 3 t minus t cubed​, for t greate
Anton [14]

Answer:

Step-by-step explanation:

The position of an object moving horizontally after t seconds is given by the function

s = 3t - t³

a) The object is stationary when there is no external force acting on the body. When the body is at rest, the body remains in a position and here is no distance covered by the object i.e s = 0

b) velocity is the change in displacement of a body with respect to time.

v = ds/dt

S = 3t - t³

V = ds/dt = 3-3t²

at t = 2

Velocity = 3-3(2)²

Velocity = 3-12

Velocity = -9m/s

c) acceleration is the change in velocity of a body with respect to time.

acceleration = dv/dt

If v = 3-3t²

a = dv/dt = -6t

When v = 0

0 = 3-3t²

-3 = -3t²

t² = 1

t = ±√1

t = 1sec

The acceleration of the object at v = 0 occurs at t = 1sec and -1sec

a = -6(1)

a = -6m/s²

d) Given the speed of the body v modelled by the function

v = 3-3t²

The speed is decreasing when it is less than zero as shown:

3-3t²< 0

3<3t²

1<t²

±1<t

1<t and -1<t

t>±1

t >1 and t>-1

The speed is decreasing when

3-3t²<0 and t>1 or t>-1

6 0
4 years ago
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