Answer:
The point of maximum growth is at x=0.82
Step-by-step explanation:
Given a logistic function
we have to find the point of maximum growth rate for the logistic function f(x).
From the graph we can see that the carrying capacity or the maximum value of logistic function f(x) is 24 and the point of maximum growth is at 
i.e between 0 to 12
So, we can take and then solve for x.
⇒ 
⇒ 
⇒ 
⇒ log 3=-1.3x
⇒ -0.4771=-1.3.x ⇒ x=0.82
Hence, the point of maximum growth is at x=0.82
Answer:
where is the graph? please provide a graph.
Answer:
16x^2 -48xy^3 +36y^6
Step-by-step explanation:
(4x-6y^(3))^(2)
FOIL
(4x-6y^3) (4x - 6y^3)
first: 4x*4x = 16x^2
outer : 4x (-6y^3) =-24xy^3
inner : 4x (-6y^3) =-24xy^3
last: -6y^3 * - 6y^3 = 36y^6
Add them together
16x^2 -24xy^3-24xy^3+36y^6
Combine like terms
16x^2 -48xy^3 +36y^6
The function f(x) is less than 0 at x < -1.8
<h3>How to analyze the graph?</h3>
The missing graph is added as an attachment
The interval where f(x) < 0 are the intervals where the y value of the function is less than 0.
This in other words, represent the negative y-axis
From the attached graph, the function f(x) is less than 0 at x < -1.8.
This extends till x = infinity
Hence, the function f(x) is less than 0 at x < -1.8
Read more about function interval at:
brainly.com/question/27831985
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