![\sqrt[3]{\dfrac{-27}{125}} = -\sqrt[3]{\left(\dfrac{3}{5}\right)^{3}}=\dfrac{-3}{5}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cdfrac%7B-27%7D%7B125%7D%7D%20%3D%20-%5Csqrt%5B3%5D%7B%5Cleft%28%5Cdfrac%7B3%7D%7B5%7D%5Cright%29%5E%7B3%7D%7D%3D%5Cdfrac%7B-3%7D%7B5%7D)
The appropriate choice appears to be ...
B. -3/5
Answer:
7 times
Step-by-step explanation:
Prob of landing on 4: 1/5
1/5 * 35 = 7
First you multiply 3 by 2.5 by 5 which should give you 37.5. For the other one you do the same but you multiply 4 by 3.5 by 4.5, it would be 63.So the second one has more volume
Answer:
The answer is B.
Step-by-step explanation:
The original graph of y = x^2 has a vertex at (0,0)
The formula for graph translations is y = (x-#)^2+#
The number inside the parentheses is a horizontal translation.
So, we are given y = (x-(-3))^2+#
The vertex of the graph moves 3 points left, since the number is negative (-3).
The number at the end of the equation is a vertical translation.
So, we are given y = (x+3)^2+4
The vertex of the graph moves 4 points up, since the number is positive (4).
The new vertex is at (-3,4)
Answer:
speed of motorcycle = 40 mph
speed of car = 50 mph
Step-by-step explanation:
Here is the complete question
A car and a motorcycle leave at noon from the same location, heading in the same direction. The average speed of the car is 30 mph slower than twice the speed of the motorcycle. In two hours, the car is 20 miles ahead of the motorcycle. Find the speed of both the car and the motorcycle, in miles per hour.
Speed = distance / time
This question would be solved using simultaneous equation
let m = average speed of the motorcycle
c = average speed of the car
c = 2m - 30 equation 1
20 =(c - m) x 2 equation 2
insert equation 1 into equation 2 and divide through by 2
10 = (2m - 30) - m
solve for m
m = 40 mph
substitute for m in equation 1
2(40) - 20 = 50 mph
