Answer:
4th term = 29
to generate the terms, substitute n = 2, 3, 4 into the rule
noting that b(1) = - 7
b(2) = b(2 - 1) + 12 = b(1) + 12 = -7 + 12 = 5
b(3) = b(3 - 1) + 12 = b(2) + 12 = 5 + 12 = 17
b(4) = b(4 - 1) + 12 = b(3) + 12 = 17 + 12 = 29
Answer:
2.46 pies (round if asked)
Step-by-step explanation:
You are eating 13.67% of <em>each</em><em> </em>pie, so you will multiply 18 × 0.1367 = 2.46
Answer:
three consecutive odd integers are.
![171, 173, 175](https://tex.z-dn.net/?f=171%2C%20173%2C%20175)
Step-by-step explanation:
Let x be the first term of odd integer,
Therefore, the second consecutive odd integers = ![x+2](https://tex.z-dn.net/?f=x%2B2)
Similarly, the third consecutive odd integers = ![x+4](https://tex.z-dn.net/?f=x%2B4)
Given:
The sum of the first term and second term is 344.
first term + second term = 344
Here first term is x and second term is
.
![x+(x+2)=344](https://tex.z-dn.net/?f=x%2B%28x%2B2%29%3D344)
![2x+2=344](https://tex.z-dn.net/?f=2x%2B2%3D344)
![2x=344-2](https://tex.z-dn.net/?f=2x%3D344-2)
![x=\frac{342}{2}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B342%7D%7B2%7D)
![x=171](https://tex.z-dn.net/?f=x%3D171)
Therefore, the first odd integers is 171.
And the second consecutive odd integers = ![x+2=171+2=173](https://tex.z-dn.net/?f=x%2B2%3D171%2B2%3D173)
Similarly, the third consecutive odd integers = ![x+4=171+4=175](https://tex.z-dn.net/?f=x%2B4%3D171%2B4%3D175)
Answer:
broooooooooooo how do you not know that not trying to be rude but anyways the answer is number 3
Answer:
620
Step-by-step explanation:
Not only you can find it, but 10 to the third power is 1,000 and 620,000 divided by 1,000 is subtracting the three 0s from it which would equal 620.