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3 years ago

Consider the functions: f(x) = 3x^2 - 5 a. Find f(5)

Mathematics

1 answer:

andre [41]3 years ago

6 0

Answer:

f(5)=70

Step-by-step explanation:

what f(5) means is put 5 in for x

so, 3(5)^2-5

3(5*5)-5

3(25)-5

75-5

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3 years ago

HELP ASAP what is the length of bd. round your answer to the nearest hundredth

bija089 [108]

Answer:

BD = 4.99 units

Step-by-step explanation:

Consider the triangle ABD only. The angle formed is 31 degrees which occurs between two sides that are AD and BC. We know that for a right angled triangle, the angle can always be taken as an angle between hypotenuse and base. Thus, The perpendicular sides is then 3 units, where base is BD and Hypotenuse is AD Using formula for tanθ tanθ = Perpendicular/Base tan31 = 3/BD 0.601 = 3/BD BD = 3/0.601 BD = 4.99 units

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2 years ago

In order to help identify baby growth patterns that are unusual, we need to construct a confidence interval of the mean head cir

sukhopar [10]

Answer:

The 99% confidence interval estimate of the mean head circumference of all 2-month-old babies is (40.18cm, 41.02cm).

Step-by-step explanation:

Our sample size is 100.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

$df = 100-1 = 99$ .

Then, we need to subtract one by the confidence level $\alpha$ and divide by 2. So:

$\frac{1-\alpha}{2} = \frac{0.01}{2} = 0.005$

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 99 and 0.005 in the t-distribution table, we have $T = 2.626$

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

$s = \frac{1.6}{\sqrt{100}} = 0.16$

Now, we multiply T and s

$M = Ts = 2.626*0.16 = 0.42$

For the lower end of the interval, we subtract the sample mean by M. So the lower end of the interval here is

$L = 40.6 - 0.42 = 40.18$ cm

For the upper end of the interval, we add the sample mean and M. So the upper end of the interval here is

$L = 40.6 + 0.42 = 41.02$ cm

The 99% confidence interval estimate of the mean head circumference of all 2-month-old babies is (40.18cm, 41.02cm).

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3 years ago