Question

A sports car can move 100.0 m in the first 4.5 s of constant acceleration.

Answer 1

The car acceleration is 22.2 repeating meters per second squared

Answer 2

Answer:

Acceleration of the car, $a=9.87\ m/s^2$

Explanation:

Initial sped of the car, u = 0

Distance covered by the car, d = 100 m

Time taken, t = 4.5 s

Let a is the acceleration of the car. It can be calculated using second equation of kinematics as :

$d=ut+\dfrac{1}{2}at^2$

$d=\dfrac{1}{2}at^2$

$a=\dfrac{2d}{t^2}$

$a=\dfrac{2\times 100}{(4.5)^2}$

$a=9.87\ m/s^2$

So, the acceleration of the car is $9.87\ m/s^2$. Hence, this is the required solution.