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marin [14]
3 years ago
6

A wave is incident on the surface of a mirror at an angle of 41° with the normal. What can you say about its angle of reflection

?
a.)It is less than the angle of incidence.

b.)It is equal to the angle of incidence.

c.)It is greater than the angle of incidence.

d.)It is zero, as it reflects along the normal
Physics
2 answers:
Oksana_A [137]3 years ago
4 0

It's angle of reflection must be 41 degrees

we know, by the first law of reflection that angle of incidence is always equal to angle of reflection..........

Viktor [21]3 years ago
4 0

Answer:

b.)It is equal to the angle of incidence.

Explanation:

As we know that as per law of reflection of light angle of incidence with respect to the normal must be equal to the angle of reflection with normal in other direction.

So we can say that

angle of incidence = angle of reflection

so here we can say that the correct answer would be

b.)It is equal to the angle of incidence.

so the light ray will reflect at the same angle as that of angle of incidence given in it

so it must be

\theta_i = \theta_r = 41^o

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A(n) 55.5 g ball is dropped from a height of 53.6 cm above a spring of negligible mass. The ball compresses the spring to a maxi
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Answer:

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Explanation:

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                                                    E_{mf}=E_{mi}

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If we manipulate the equation we have that:

                                                    k=\frac{2mgh}{d^{2} }

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                                              k=\frac{0.58306\ \frac{kgm^{2}}{s^{2}}}{2.398x10^{-3}m^{2}}

                                                     k=243\ \frac{N}{m}

                                                   

                             

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