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2 years ago

8

The gas in the balloon has a mass of 0.032 kg. The balloon has a volume of 0.025 m3. Calculate the density of the gas in the bal

loon.
[2 marks]

1 answer:

ale4655 [162]2 years ago

5 0

Answer:

0.0008

Explanation:

D=M*V

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What is the term for the ability to cause change in matter?

Leokris [45]

Answer:

A. Energy

Explanation:

You can change energy from one form to another when you lift your arm or take a step. Energy is used to move matter. In this scenario, the matter would be you.

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2 years ago

In what way is a piano an example of a quantized system?

uranmaximum [27]

When you play a piano, your energy increases in a uniform, continuous manner and is therefore quantized.When you play a piano, you can press only on individual keys, so that your energy is restricted to certain values and is therefore quantized.

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3 years ago

ndicate whether the statement is true or false. Whenever we move, we alter the rate at which we move into the future. A. True B.

Ksju [112]

Whenever we move, we alter the rate at which we move into the future. This statement is true.

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2 years ago

On a balanced seesaw, a boy three times as heavy as his partner sits

slega [8]

Answer:

1/3 the distance from the fulcrum

Explanation:

On a balanced seesaw, the torques around the fulcrum calculated on one side and on another side must be equal. This means that:

$W_1 d_1 = W_2 d_2$

where

W1 is the weight of the boy

d1 is its distance from the fulcrum

W2 is the weight of his partner

d2 is the distance of the partner from the fulcrum

In this problem, we know that the boy is three times as heavy as his partner, so

$W_1 = 3 W_2$

If we substitute this into the equation, we find:

$(3 W_2) d_1 = W_2 d_2$

and by simplifying:

$3 d_1 = d_2\\d_1 = \frac{1}{3}d_2$

which means that the boy sits at 1/3 the distance from the fulcrum.

8 0

3 years ago

A father fashions a swing for his children out of a long rope that he fastens to the limb of a tall tree. As one of the children

trasher [3.6K]

Answer:

The centripetal acceleration of the child at the bottom of the swing is 15.04 m/s².

Explanation:

The centripetal acceleration is given by:

$a_{c} = \frac{v^{2}}{r}$

Where:

$v^{2}$ : is the tangential speed = 9.50 m/s

r: is the distance = 6.00 m

Hence, the centripetal acceleration is:

$a_{c} = \frac{v^{2}}{r} = \frac{(9.50 m/s)^{2}}{6.00 m} = 15.04 m/s^{2}$

Therefore, the centripetal acceleration of the child at the bottom of the swing is 15.04 m/s².

I hope it helps you!

3 0

2 years ago

Read 2 more answers