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Alika [10]
3 years ago
7

Write the reason behind the atmosphere does not escape away from the earth​

Physics
2 answers:
ra1l [238]3 years ago
7 0

Earth's gravity is strong enough to hold onto its atmosphere and keep it from drifting into space.

Thanks to Earth's gravity, the atmosphere doesn't escape into space. Gravity pushes down on Earth's atmosphere, keeping its air from drifting away, according to the National Oceanic and Atmospheric Administration's SciJinks online earth science education website.

postnew [5]3 years ago
4 0

Answer:

i knew it but now i dont

Explanation:

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Suppose two comets, comet A and comet B, were orbiting the sun, having the same average orbital radii. If comet A had a higher o
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Answer:

a. A

Explanation:

Kepler's First Law says that the orbits of planets are ellipses with the sun at one focus of the ellipse. Moreover, Kepler’s Second Law says that the line joining the planet to the sun sweeps out equal areas in equal times as it moves along its orbit. Finally, Kepler’s Third Law says that the ratio of the squares of the periods for two planets is equal to the ratio of the cubes of their semi-major axes.

By these laws, the comet A will have lower orbital speed.

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A viscous liquid is sheared between two parallel disks of radius �, one of which rotates with angular speed Ω, while the other i
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Answer:

Upper disk rotates at a constant angular velocity. The velocity at any height from stationery disk, say at x metres

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U_o=r\omega (\frac {x}{h})

The radial component of velocity is given as

U_r=0

The z component of velocity is also given as  

W=0

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3 years ago
What happens to a liquid when it loses energy
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3 years ago
single goose sounds a loud warning when an intruder enters the farmyard. Some distance from the goose, you measure the sound lev
Goryan [66]

Answer:

The sound level of the 26 geese is  Z_{26}= 96.15 dB

Explanation:

From the question we are told that

    The  sound level is Z_1 =  81.0 \ dB

     The number of geese is N = 26

Generally the intensity level of sound is mathematically represented as

        The intensity of sound level in dB  for one  goose is mathematically represented as

                       Z_1 = 10 log [\frac{I}{I_O} ]

Where I_o is the  threshold level of intensity with value  I_o = 1*10^{-12} \  W/m^2

            I is the intensity for one goose in W/m^2

For 26 geese the intensity would be  

          I_{26} = 26 * I

   Then  the intensity of 26 geese in dB is  

              Z_{26} = 10 log[\frac{26 I }{I_o} ]

               Z_{26} = 10 log (\ \ 26 *  [\frac{ I }{I_o} ]\ \ )

               Z_{26} = 10 log (\ \ 26  \ \ ) *   (\ \  10 log [\frac{ I }{I_o} ]\ \ )

 From the law of logarithm we have that

              Z_{26} = 10 log 26 +  10 log [\frac{I}{I_0} ]

                    = 14.15 + 82

                    Z_{26}= 96.15 dB

               

               

           

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3 years ago
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The average rate of change of distance over the time interval 
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