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sesenic [268]
3 years ago
13

What is the following sum? 3b^2(^3 √54a) + 3(^3 √2ab^6)

Mathematics
2 answers:
sveticcg [70]3 years ago
8 0

Answer:

12b^2\sqrt[3]{2a}

Step-by-step explanation:

Our original expression is

3b^2(\sqrt[3]{54a})+3(\sqrt[3]{2ab^6})

We will first expand the terms under the cubed roots:

3b^2(\sqrt[3]{3*3*3*2*a})+3(\sqrt[3]{2a*b*b*b*b*b*b})

Since we have cubed roots, we are looking for groups of 3 factors.  In the first term, we have three 3's; this means we can bring a 3 out.  In the second term, we have six b's; this means we can bring out 2 b's:

3b^2(3\sqrt[3]{2a})+3(b^2\sqrt[3]{2a})\\\\=9b^2\sqrt[3]{2a}+3b^2\sqrt[3]{2a}

Lastly, combine like terms:

12b^2\sqrt[3]{2a}

Ksenya-84 [330]3 years ago
6 0

Answer

12b^{2} \sqrt[3]{2a}

Step-by-step explanation:

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Martine’s town is building a volleyball court based on a scale drawing that is 40cm to 80cm and uses the scale 1cm:22.5cm write
never [62]

Answer:

y=22.5x

Step-by-step explanation:

we have that

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\frac{1}{22.5}\frac{cm}{cm}

we know that

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Let

x -----> drawing court lengths in cm

y ----> court lengths in cm

For x=40 cm

\frac{1}{22.5}\frac{cm}{cm}=\frac{40}{y}\frac{cm}{cm}\\\\y=40*22.5\\\\y=900\ cm

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\frac{1}{22.5}\frac{cm}{cm}=\frac{80}{y}\frac{cm}{cm}\\\\y=80*22.5\\\\y=1,800\ cm

Find the equation for the proportional relation ship between drawing court lengths x in centimeters and court lengths in y centimeters

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k=y/x -----> k=900/40=22.5

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3 years ago
Subtract.
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(x+1)-(-2x-5)
=x+1+2x+5
=3x+6
=3(x+2)
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