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Ratling [72]
3 years ago
7

Write the equation of a line that passes through the points (-2, -8) and (2, -6).

Mathematics
1 answer:
Anna [14]3 years ago
5 0

Answer:

y = \frac{1}{2} x - 7

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (- 2, - 8) and (x₂, y₂ ) = (2, - 6)

m = \frac{-6+8}{2+2} = \frac{2}{4} = \frac{1}{2} , thus

y = \frac{1}{2} x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (2, - 6), then

- 6 = 1 + c ⇒ c = - 6 - 1 = - 7

y = \frac{1}{2} x - 7 ← equation of line

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Step-by-step explanation:

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The numerator of a fraction (which is in its simplest form) is 5 less than the denominator. If the numerator is multiplied by 2,
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Here's the tricky part.
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16 = 2d
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Let's see if it checks out.
n = 3
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3 0
3 years ago
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TEA [102]
<h3>Answer:</h3>
  • A (graph below)
  1. Not appropriate
  2. Appropriate
  3. Not appropriate
<h3>Step-by-step explanation:</h3>

1st Question

The transformation g(x) = f(x -h) +k translates a function h units to the right and k units upward. Your expression has (h, k) = (-2, -4), so the graph of the function will be translated 2 units left and 4 units down.

A distinctive feature of the cube root curve is the vertical spot normally at point (0, 0). You're looking for the graph that has that relocated to (-2, -4). Graph A matches that.

2nd Question

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