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Ratling [72]
3 years ago
7

Write the equation of a line that passes through the points (-2, -8) and (2, -6).

Mathematics
1 answer:
Anna [14]3 years ago
5 0

Answer:

y = \frac{1}{2} x - 7

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (- 2, - 8) and (x₂, y₂ ) = (2, - 6)

m = \frac{-6+8}{2+2} = \frac{2}{4} = \frac{1}{2} , thus

y = \frac{1}{2} x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (2, - 6), then

- 6 = 1 + c ⇒ c = - 6 - 1 = - 7

y = \frac{1}{2} x - 7 ← equation of line

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The correct works are:

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<h3>Function Notation</h3>

The function is given as:

Blue(s) = 2s^2 + 3

The interpretation when Steven is asked to calculate Blue(s + h) is that:

Steven is asked to find the output of the function Blue, when the input is s + h

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Blue(s + h) = 2(s + h)^2 + 3

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Expand the bracket

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So, the correct work is:

Blue(s + h) = 2s^2 + 4sh + 2h^2 + 3

<h3>Simplifying Difference Quotient</h3>

In (a), we have:

Blue(s + h) = 2s^2 + 4sh + 2h^2 + 3

Blue(s) = 2s^2 + 3

The difference quotient is represented as:

\frac{f(x + h) - f(x)}{h}

So, we have:

\frac{Blue(s + h) - Blue(s)}{h} = \frac{2s^2 + 4sh + 2h^2 + 3 - 2s^2 - 3}{h}

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\frac{Blue(s + h) - Blue(s)}{h} = \frac{4sh + 2h^2}{h}

Evaluate the quotient

\frac{Blue(s + h) - Blue(s)}{h} = 4s + 2h

Hence, the correct work is:

\frac{Blue(s + h) - Blue(s)}{h} = 4s + 2h

Read more about function notations at:

brainly.com/question/13136492

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