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Katen [24]
2 years ago
14

Find the value of M and n

Mathematics
1 answer:
DochEvi [55]2 years ago
7 0
8/ Sine 50 = n/ Sine 90
8 sine 90 = n Sine 50
8 sine 90 / sine 50 = n
n = 10.4

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Step-by-step explanation:

<u>A.-6-3 = -9</u>

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3 years ago
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ella [17]
What do you need help with?
4 0
2 years ago
Can someone pls help me / alguien me puede ayudar
user100 [1]

Answer:

The simplified expression is:

\frac{2}{5}y+\frac{1}{5}x-0.2y-6+\left(-2\right)=0.2y+0.2x-8

Step-by-step explanation:

Given the expression

\frac{2}{5}y+\frac{1}{5}x-0.2y-6+\left(-2\right)

\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a

=\frac{2}{5}y+\frac{1}{5}x-0.2y-6-2

\mathrm{Group\:like\:terms}

=\frac{2}{5}y-0.2y+\frac{1}{5}x-6-2

Add similar elements

=0.2y+\frac{1}{5}x-6-2

=0.2y+\frac{x}{5}-6-2

=0.2y+\frac{x}{5}-8

=0.2y+0.2x-8

Thus, the simplified expression is:

\frac{2}{5}y+\frac{1}{5}x-0.2y-6+\left(-2\right)=0.2y+0.2x-8

6 0
3 years ago
If the point (2, -10) lies on the graph of a direct variation, which represents the direct variation equation?
Zanzabum

\bf \qquad \qquad \textit{direct proportional variation} \\\\ \textit{\underline{y} varies directly with \underline{x}}\qquad \qquad y=kx\impliedby \begin{array}{llll} k=constant\ of\\ \qquad variation \end{array} \\\\[-0.35em] ~\dotfill\\\\ (\stackrel{x}{2},\stackrel{y}{-10})~~ \textit{we know } \begin{cases} x=2\\ y=-10 \end{cases}\implies -10=k2\implies \cfrac{-10}{2}=k\implies -5=k \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill y=-5x~\hfill

8 0
3 years ago
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