Can y’all help me on question 6?!

6.

dimulka [17.4K]

So car A travels Distance = 60 km/hr*(1+x)

Car B travels Distance = 75 km/hr(x)

Where x is the time in hours.

Those two equations are equal when on overtakes the other

so:

60 +60x = 75x

60=15x

x=4, but my expression is written to count from when car B commenced travel. So total time is 5 hours from the car A setting off.

3 0

2 years ago

Read 2 more answers

Solve for a. a+(−4)=−13

dangina [55]

In your equation: a+(-4)=-13
you then add four to each side,
so a= negative 13 plus 4
so a= -9

6 0

3 years ago

Read 2 more answers

ACDF,BE is a mid segment what is x?

Ksenya-84 [330]

Answer:

X= 15

Step-by-step explanation:

the above equation will be used to determine the value of x.

6x-12= 2x+20+18

6x-2x = 20+12+18

4x= 60.

X= 60/4

X= 15

x = 15

7 0

3 years ago

Select all the expressions that are equivalent to 8 - X.

oee [108]

answer is :

B, C, G

hope this helps

4 0

3 years ago

How much coffee costing $4 a pound should be mixed with 3 pounds of coffee costing 4.50 a pound to obtain a mixture costing $4.3

Aleks04 [339]

Answer:

The quantity of coffee costing $4 a pound in the coffee mixture is 2 pounds.

Step-by-step explanation:

Given: Coffee costing $4 a pound is mixed with 3 pounds of coffee costing 4.50 a pound to obtain a mixture costing $4.30 a pound.

We have to find the quantity of coffee costing $4 a pound in the mixture.

Let x represent the number of pounds of $4 coffee.

Cost of one pound = 4x.

Cost of 3 pounds of coffee costing 4.50 a pound = 3(4.50)

Cost of mixture costing $4.30 a pound = (x+3)(4.30)

According to given problem,

$4x+3(4.50)=(x+3)4.30$

Solving for x, we get,

$\Rightarrow 4x+13.5=4.30x+12.9$

Rearranging like term together, we get,

$\Rightarrow 13.5-12.9=4.30x-4x$

$\Rightarrow 0.6=0.30x$

$\Rightarrow x=2$

Thus, the quantity of coffee costing $4 a pound in the coffee mixture is 2 pounds.

3 0

3 years ago