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umka21 [38]
3 years ago
15

Please help immediately ​

Mathematics
1 answer:
Burka [1]3 years ago
8 0

Answer:    f'(1)=\dfrac{4}{2y+1}

<u>Step-by-step explanation:</u>

To find the tangent, you need to find the derivative with respect to x.

Then substitute x = 1 into the derivative.

Given:         0 = 2x² - xy - y²

Derivative:  0 = 4x - y' - 2yy'

Solve for y': 2yy' + y' = 4x

                   y'(2y + 1) = 4x

                   y'=\dfrac{4x}{2y+1}

\text{Substitute x = 1:}\quad y'(1)=\dfrac{4}{2y+1}

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