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strojnjashka [21]
3 years ago
7

Definition of positive slope

Mathematics
2 answers:
AysviL [449]3 years ago
8 0

Answer: A positive slope means that two variables are positively related—that is, when x increases, so does y, and when x decreases, y decreases also. Graphically, a positive slope means that as a line on the line graph moves from left to right, the line rises.

Step-by-step explanation:

ddd [48]3 years ago
5 0

Answer:

A positive slope means that two variables are positively related—that is, when x increases, so does y, and when x decreases, y decreases also. Graphically, a positive slope means that as a line on the line graph moves from left to right, the line rises.

Step-by-step explanation:

mark me as brainliest pls :)

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If the complement of an angle is 40 less than its supplement, find the angle.
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River rambler charges $25 per day to rent a kayak. How much will it cost to rent a kayak for 5 days? Write and solve an equation
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Answer:

C=25d

Step-by-step explanation:

We write an equation where C or cost is my output and d or days is my input. I should be able to put in any number of days and find the cost. Let's gather some data:

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Day 1 $25(1)=25 cost

Day 2 $25(2)=50 cost

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4 years ago
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The lengths of the sides of a triangle are in the extended ratio 5: 8:10. The perimeter of the triangle is 115 cm. What are the
leva [86]

Given :

  • The length of the sides of the triangle are in the ratio 5:8:10 .
  • The Perimeter of the Triangle is 115 cm.

To Find :

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Solution :

Let us assume the sides be 5x cm, 8x cm and 10x cm.

We know,

\qquad{ \bold{ \pmb{Sum \: of \: all \: sides \: of \: the \: triangle = Perimeter_{(Triangle)}}}}

So, Substituting the values :

\qquad { \dashrightarrow{ \sf{5x + 8x + 10x = 115}}}

\qquad { \dashrightarrow{ \sf{23x= 115}}}

\qquad { \dashrightarrow{ \sf{ \dfrac{23x}{23} = \dfrac{115}{23} }}}

\qquad { \dashrightarrow{ \bf{ x = 5 }}}

Therefore,

The length of the sides of the triangle are :

\qquad { \dashrightarrow{ \sf{ 5x \: cm= 5 \times 5 \: cm = \bf \: 25\: cm }}}

\qquad { \dashrightarrow{ \sf{ 8x \: cm= 8 \times 5 \: cm = \bf \: 40 \: cm }}}

\qquad { \dashrightarrow{ \sf{ 10x \: cm= 10 \times 5 \: cm = \bf \: 50 \: cm }}}

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