Answer:
Step-by-step explanation:
Given
Required
Determine the type of roots
Represent Discriminant with D; such that
D is calculated as thus
And it has the following sequence of results
When 
then the roots of the quadratic equation are real but not equal
When 
then the roots of the quadratic equation are real and equal
When 
then the roots of the quadratic equation are complex or imaginary
Given that ; This means that and base on the above analysis, we can conclude that the roots of the quadratic equation are complex or imaginary
Answer:
Step-by-step explanation:
Please excuse my handwriting lol.
Answer:
x = 5 and -2
Step-by-step explanation:
Given the function of x to be;
f(x) = (x-5)(x+2)/x+1
The value of x that will make the function zero can be calculated for by equating the given function to zero first to have;
If f(x) = 0, then;
(x-5)(x+2)/x+1 = 0
Cross multiplying;
(x-5)(x+2) = 0
(x-5) = 0 and x+2 = 0
x = 5 and x = -2
The value of x that will make the function zero is therefore 5 and -2
The answer to your question is TRUE
Use distributie property which is
a(b+c)=ab+ac
therefor
6x(x-4)=6x^2-24x
distribute the negative 1 infroont of the (9x-1)
-1(9x-1)=-9x+1
now we have
6x^2-24x-16x^2-9x+1
gropu like terms
6x^2-16x^2-24x-9x+1
add like terms
-10x^2-33x+1 is simplest form
