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Ann [662]
3 years ago
13

Find the length of side ab give answer to 1dpB is 62 degrees And hypotenuse is 12cm

Mathematics
1 answer:
pshichka [43]3 years ago
4 0
Iwteiwyeoe e to do that and i don’t even exist and i is so much more comfortable than that what do you
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help,for,points and brainliest math easy math hi a b c d e f g h i j k l m n o p q r s t u v w s y and z
Marrrta [24]
The answers are
D. 21
E. 30
3 0
2 years ago
What is 2005 as a percent​
makkiz [27]

Answer:

Here’s your answer!

Step-by-step explanation:

2005 as a percent is 200500%!

Hope this helps

Dont forget to smash that heart at the bottom <3

Plz Mark Brainliest

Need help solving future problems like this? Use GetEasySolution.com for a calculator that works for decimals,percents and more! ( I am not with them but the calculator did help me a while back so here’s a recommendation)

Have a great day,youre amazing!

4 0
2 years ago
Read 2 more answers
You have 6 pints of glaze. It takes 7/8 of a pint to glaze a bowl and 9/16 of a pint to glaze a plate.
son4ous [18]

Answer:

a. How many bowls could you glaze?

6 bowls

How many plates could you glaze?

10 plates

b. You want to glaze 5 bowls, and then use the rest for plates.

How many plates can you glaze?

2 plates

How much glaze will be left over?

8/9 of glaze would be left

c. How many of each object could you glaze so that there is no glaze left over? Explain how you found your answer.

4 4/23 bowls and 4 4/23 plates

Step-by-step explanation:

We are told in the question

Number of pints of glaze = 6 pints

Number of pints to glaze a bowl= 7/8 of pint

Number of pints to glaze a plate = 9/16 of a pint

a.

How many bowls could you glaze?

7/8 pint = 1 bowl

6 pints = x

Cross Multiply

x = 6 pints/ 7/8

= 6 × 8/7

= 48/7

= 6.8571428571 bowls

We can only glaze whole numbers of a bowl, hence, we can only glaze 6 bowls

How many plates could you glaze?

9/16 pint = 1 bowl

6 pints = y

y = 6 pints/ 9/16

= 6 × 16/9

= 10.666666667 plates

We can only glaze whole number of a plate, hence, we can only glaze 10 plates

b. You want to glaze 5 bowls, and then use the rest for plates.

1 bowl = 7/8 pints

5 bowls = z

Cross Multiply

z = 5 × 7/8pints

= 4 3/8 pints of glaze would be used for bowls

How many plates can you glaze?

The rest is for plates, hence:

The amount of glaze left for plates is calculated as:

6 pints - 4 3/8

1 5/8 pints of glaze would be left over to glaze plates.

So therefore,

9/16 pints = 1 plate

1 5/8 pints =

= 2 8/9

Hence we can only glaze 2 plates

How much glaze will be left over?

2 8/9 pints - 2 pints

= 8/9 pints of glaze.

c. How many of each object could you glaze so that there is no glaze left over?

We have 6 pints of glaze

Number of pints to glaze a bowl= 7/8 of pint

Number of pints to glaze a plate = 9/16 of a pint

Let the number of each objects be represented by x

7/8 × x + 9/16 × x = 6 pints

= 4 4/23 bowls and 4 4/23 plates

3 0
2 years ago
Can someone help me plz
VikaD [51]
Name all the angles that have v as a vertex
4 0
3 years ago
Abner wants to create a shopping budget where he spends less than $80 per month on clothes. He also wants to spend at least thre
strojnjashka [21]

Answer:

D) Abner can spend $60 per month on school clothes and $20 per month on gym clothes and stay within his budget.

Step-by-step explanation:

In the problem it states that Abner will spend 3 times more on (s)school clothes than (g) gym clothes.

So it would appear as s ≥ 3g.

If we plug in $60 as s (school clothes) and $20 as g (gym clothes), the statement is true.

60 ≥ 3(20)

60 ≥ 60. These numbers make the linear system true.

If you have trouble with this, an easy way to find this answer is simply creating the linear system that represents the problem, (he will buy 3 times more school clothes than gym clothes) s ≥  3g and plug in each variable from the answer choices until you find the variables that make the linear system true.


6 0
3 years ago
Read 2 more answers
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