Cat are 1m cub in centimetri

The probability that a randomly selected 3-year-old male chipmunk will live to be 4 years old is 0.96516.

mezya [45]

Using the binomial distribution, it is found that there is a:

a) The probability that two randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.93153 = 93.153%.

b) The probability that six randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.80834 = 80.834%.

c) The probability that at least one of six randomly selected 3-year-old male chipmunks will not live to be 4 years old is 0.19166 = 19.166%. This probability is not unusual, as it is greater than 5%.

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For each chipmunk, there are only two possible outcomes. Either they will live to be 4 years old, or they will not. The probability of a chipmunk living is independent of any other chipmunk, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.
n is the number of trials.
p is the probability of a success on a single trial.

In this problem:

0.96516 probability of a chipmunk living through the year, thus $p = 0.96516$

Item a:

Two is P(X = 2) when n = 2, thus:

$P(X = 2) = C_{2,2}(0.96516)^2(1-0.96516)^{0} = 0.9315$

The probability that two randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.93153 = 93.153%.

Item b:

Six is P(X = 6) when n = 6, then:

$P(X = 6) = C_{6,6}(0.96516)^6(1-0.96516)^{0} = 0.80834$

The probability that six randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.80834 = 80.834%.

Item c:

At least one not living is:

$P(X < 6) = 1 - P(X = 6) = 1 - 0.80834 = 0.19166$

The probability that at least one of six randomly selected 3-year-old male chipmunks will not live to be 4 years old is 0.19166 = 19.166%. This probability is not unusual, as it is greater than 5%.

A similar problem is given at brainly.com/question/24756209

6 0

2 years ago

Use the drawing tool(s) to form the correct answer on the provided graph.

NikAS [45]

Answer:

Here's one way to do it

Step-by-step explanation:

1. Solve the inequality for y

5x - y > -3

-y > -5x - 3

y < 5x + 3

2. Plot a few points for the "y =" line

I chose

\begin{gathered}\begin{array}{rr}\mathbf{x} & \mathbf{y} \\-2 & -7 \\-1 & -2 \\0 & 3 \\1 & 8 \\2 & 13 \\\end{array}\end{gathered}

x

−2

−1

0

1

2

y

−7

−2

3

8

13

You should get a graph like Fig 1.

3. Draw a straight line through the points

Make it a dashed line because the inequality is "<", to show that points on the line do not satisfy the inequality.

See Fig. 2.

4. Test a point to see if it satisfies the inequality

I like to use the origin,(0,0), for easy calculating.

y < 5x + 3

0 < 0 + 3

0 < 3. TRUE.

The condition is TRUE.

Shade the side of the line that contains the point (the bottom side).

And you're done (See Fig. 3).

6 0

2 years ago

Fractions and Mixed numbers:

LiRa [457]

28/8 = 3 remainder 4 so 3 4/8(fraction) or 3 1/2
You would want to divide the minutes to the songs so you can find out how long one song is, but sense there was a remainder you could turn it into a fraction or you could keep diving. In this case you would want to stop. To find the fraction here is a formula the divisor is the denominator, the numerator is the remainder and the whole number is the number you get that is behind the remainder

3 0

2 years ago

Jasmine filled her bag with 12 strawberries. George filled his bag with 6 times as many strawberries as jasmine. How many strawb

Allisa [31]

Since Jasmine has 12 strawberries and George has 6 times has many, you can multiply 12 by 6 to get the number of strawberries George has in his bag.

6 x 12 = 72.

George has 72 strawberries in his bag

8 0

3 years ago

Read 2 more answers

Carlos downloaded a pattern from the Internet for making a table with an

Zepler [3.9K]

Answer: did you ever get the answer?

Step-by-step explanation:

I need it too lol

4 0

2 years ago